在 javascript 中获取引号中的字符串

Question

我如何编写一个函数来从一个字符串中获取引号中的所有字符串？该字符串可能包含转义引号。我试过正则表达式，但由于正则表达式没有类似状态的功能，所以我无法做到这一点。示例：

apple banana "pear" strawberries "\"tomato\"" "i am running out of fruit\" names here"

应该return像['pear', '"tomato"', 'i am running out of fruit" names here']

这样的数组

也许有 split 的东西可以工作，虽然我不知道如何。

Answer 1

试试这个：

function getStringInQuotes(text) {

    const regex = const regex = /(?<=")\w+ .*(?=")|(?<=")\w+(?=")|\"\w+\"(?=")|(?<=" )\w+(?=")|(?<=")\w+(?= ")/g

    return text.match(regex);

}

const text = `apple banana "pear" strawberries "\"tomato\"" "i am running out of fruit\" names here"`;

console.log(getStringInQuotes(text));

Answer 2

我使用以下函数解决了这个问题：

const getStringInQuotes = (text) => {

    let quoteTogether = "";
    let retval = [];
    let a = text.split('"');
    let inQuote = false;
    for (let i = 0; i < a.length; i++) {
        if (inQuote) {
            quoteTogether += a[i];
            if (quoteTogether[quoteTogether.length - 1] !== '\') {
                inQuote = false;
                retval.push(quoteTogether);
                quoteTogether = "";
            } else {
                quoteTogether = quoteTogether.slice(0, -1) + '"'
            }
        } else {
            inQuote = true;
        }
    }
    return retval;
}

在 javascript 中获取引号中的字符串

Getting string in quotes in javascript

javascript

quotes

parsing

literals