如何将数据框中的第二列除以第一列？

Question

     DP 1       DP 2        DP 3       DP 4        DP 5         DP 6        DP 7        DP 8       DP 9        DP 10
 3,57,848    11,24,788   17,35,330   22,18,270   27,45,596   33,19,994   34,66,336   36,06,286   38,33,515   39,01,463 
 3,52,118    12,36,139   21,70,033   33,53,322   37,99,067   41,20,063   46,47,867   49,14,039   53,39,085  
 2,90,507    12,92,306   22,18,525   32,35,179   39,85,995   41,32,918   46,28,910   49,09,315      
 3,10,608    14,18,858   21,95,047   37,57,447   40,29,929   43,81,982   45,88,268          
 4,43,160    11,36,350   21,28,333   28,97,821   34,02,672   38,73,311              
 3,96,132    13,33,217   21,80,715   29,85,752   36,91,712                  
 4,40,832    12,88,463   24,19,861   34,83,130                      
 3,59,480    14,21,128   28,64,498                          
 3,76,686    13,63,294                              
 3,44,014

我有这个三角形数据框 (df1)，我想计算包含 result:second_column(df2)/first_column(df2) 和 third_column 的新数据框 (df2) (df2)/second_column(df2) 等等..

我这样试过（我知道错了）

for colname, col in df1.iteritems():
            df1[colname7] = df1['second_column']/df1['first_column']

我想要这样的 df2:

  DP 1   DP 2    DP 3    DP 4    DP 5    DP 6    DP 7    DP 8    DP 9   DP 10
 3.14    1.54    1.28    1.24    1.21    1.04    1.04    1.06    1.02    -   
 3.51    1.76    1.55    1.13    1.08    1.13    1.06    1.09    -      
 4.45    1.72    1.46    1.23    1.04    1.12    1.06    -          
 4.57    1.55    1.71    1.07    1.09    1.05    -              
 2.56    1.87    1.36    1.17    1.14    -                  
 3.37    1.64    1.37    1.24    -                      
 2.92    1.88    1.44    -                          
 3.95    2.02    -                              
 3.62    -

感谢您的宝贵时间..

Answer 1

首先你需要去掉逗号并将dataframe转换为float类型：

df2 = df1.replace(',', '', regex = True).astype(float)

那么就可以直接平移一次列来除：

df2 = df2.shift(-1, axis = 1).div(df2)

输出

df2
       DP 1      DP 2      DP 3      DP 4      DP 5      DP 6      DP 7      DP 8      DP 9  DP 10
0  3.143200  1.542806  1.278299  1.237719  1.209207  1.044079  1.040374  1.063009  1.017725    NaN
1  3.510582  1.755493  1.545286  1.132926  1.084493  1.128106  1.057268  1.086496       NaN    NaN
2  4.448450  1.716718  1.458257  1.232079  1.036860  1.120010  1.060577       NaN       NaN    NaN
3  4.568002  1.547052  1.711784  1.072518  1.087360  1.047076       NaN       NaN       NaN    NaN
4  2.564198  1.872956  1.361545  1.174217  1.138315       NaN       NaN       NaN       NaN    NaN
5  3.365588  1.635679  1.369162  1.236443       NaN       NaN       NaN       NaN       NaN    NaN
6  2.922798  1.878099  1.439393       NaN       NaN       NaN       NaN       NaN       NaN    NaN
7  3.953288  2.015651       NaN       NaN       NaN       NaN       NaN       NaN       NaN    NaN
8  3.619179       NaN       NaN       NaN       NaN       NaN       NaN       NaN       NaN    NaN
9       NaN       NaN       NaN       NaN       NaN       NaN       NaN       NaN       NaN    NaN

您可以选择舍入：

df2 = df2.round(2)

如何将数据框中的第二列除以第一列？

How to divide second column by first column in dataframe?

python

dataframe

pandas

triangle