互斥量创建会导致分段错误

Question

我不明白为什么在创建以下互斥体时会出现分段错误：

#include <stdlib.h>
#include <string.h>
#include <stdio.h>

#include <semaphore.h> // include POSIX semaphores
#include <fcntl.h>



struct semaphoreStruct{
  sem_t *mutex;
};




struct semaphoreStruct *semaphore_list;

int main(){

  sem_unlink("MUTEX");
  semaphore_list->mutex = sem_open("MUTEX", O_CREAT|O_EXCL,0700,1);
  return 0;
}

如有任何帮助，我们将不胜感激！

Answer 1

由于未为 struct semaphoreStruct *semaphore_list 指针分配内存而出现分段错误。

#include <stdlib.h>
#include <string.h>
#include <stdio.h>

#include <semaphore.h> // include POSIX semaphores
#include <fcntl.h>

struct semaphoreStruct{
  sem_t *mutex;
};

struct semaphoreStruct *semaphore_list;

int main(){
  semaphore_list = malloc(sizeof(struct semaphoreStruct)); //allocate the memory for the struct
  sem_unlink("MUTEX");
  semaphore_list->mutex = sem_open("MUTEX", O_CREAT|O_EXCL,0700,1);
  return 0;
}

互斥量创建会导致分段错误

Mutex creation creates a segmentation fault

c

mutex

semaphore

segmentation-fault