Laravel 8:将工厂属性传递给子关系
Laravel 8: Passing Factory properties into children relationships
我们目前正在开发 laravel 8 应用程序。我们正在尝试创建工厂来为基于手动/开发人员的应用程序测试创建一些虚拟数据。
我的主数据库播种器的当前代码如下:
class DatabaseSeeder extends Seeder
{
public function run()
{
$this->call([
UserTableSeeder::class,
]);
\App\Models\User::factory(10)->create();
\App\Models\Activity::factory(5)->create();
/* 1. try
$tenFact = \App\Models\Tenant::factory(2)->has(
\App\Models\Project::factory(2)->state(
function (array $attributes, \App\Models\Tenant $tenant) {
return ['tenant_id' => $attributes['id']];
}
)->hasTasks(5)->hasLocation()
)->hasContracts(3)->create();
*/
/* Currently being used: */
\App\Models\Tenant::factory(10)->has(
\App\Models\Project::factory(5)->hasTasks(5)->hasLocation()
)->hasContracts(3)->create();
}
ProjectFactory.php:
class ProjectFactory extends Factory
{
protected $model = Project::class;
public function definition()
{
return [
'name' => 'Projekt: '. $this->faker->name,
'budget' => $this->faker->randomDigitNotNull*1000,
'progress' => $this->faker->randomDigitNotNull*10,
'budget_used' => $this->faker->randomDigitNotNull*50,
//'tenant_id' => Tenant::factory(),
'location_id' => Location::factory()->hasTenant(1),
];
}
}
LocationFactory.php:
class LocationFactory extends Factory
{
protected $model = Location::class;
public function definition()
{
return [
'name' => 'Standort: ' . $this->faker->company,
'street' => $this->faker->streetName,
'house_number' => $this->faker->buildingNumber,
'house_addition' => $this->faker->secondaryAddress,
'zip' => $this->faker->postcode,
'city' => $this->faker->city,
'tenant_id' => Tenant::factory(),
];
}
}
我们的关系是这样的:
Tenant
|-- Project (has: tenant_id, but also has location_id)
| | -- Task (has: project_id)
|-- Locations (has: tenant_id)
|-- Contracts (has: tenant_id)
使用上面命名的 Tenant-Factory 创建数据集时,会发生以下情况:
- Tenant->id 正在传递给 Project(tenant_id)
但是:Tenant->id 没有传递给 Location(这取决于租户 id 但也用于 Project)。
我们如何将 \App\Models\Tenant::factory(10) 的 id 传递给 Project::factory(5)->hasTasks(5)->hasLocation()?
此外,我们确实有问题,即使我们请求 10 个租户,我们也会得到大约 60 个,因为 Location/Project 在它们应该使用现有对象时创建新对象。
class ProjectFactory extends Factory
{
$location_ids = App\Models\Location::pluck('id')->toArray();
protected $model = Project::class;
public function definition()
{
return [
'name' => 'Projekt: '. $this->faker->name,
'budget' => $this->faker->randomDigitNotNull*1000,
'progress' => $this->faker->randomDigitNotNull*10,
'budget_used' => $this->faker->randomDigitNotNull*50,
//'tenant_id' => Tenant::factory(),
'location_id'=> $faker->randomElement($location_ids),
];
}
}
class LocationFactory extends Factory
{
$tenant_ids = App\Models\Tenant::pluck('id')->toArray();
protected $model = Location::class;
public function definition()
{
return [
'name' => 'Standort: ' . $this->faker->company,
'street' => $this->faker->streetName,
'house_number' => $this->faker->buildingNumber,
'house_addition' => $this->faker->secondaryAddress,
'zip' => $this->faker->postcode,
'city' => $this->faker->city,
'tenant_id'=> $faker->randomElement($tenant_ids),
];
}
}
我放弃了使用 Tenant-Factory 的链式使用 - 我最终使用了一些 for-Loop,通过使用 laravels for() 和 state() 方法将相关对象连接到每个用户:
for ($i=0; $i < 10 ; $i++) {
$tenant = \App\Models\Tenant::factory()->hasContracts(3)->create();
for ($j=0; $j < 5; $j++) {
$location = \App\Models\Location::factory(1)->for($tenant)->create();
$project = \App\Models\Project::factory(1)->state([
'location_id' => $location->first()['id'],
'tenant_id' => $tenant['id']])->hasTasks(5)->create();
}
}
我们目前正在开发 laravel 8 应用程序。我们正在尝试创建工厂来为基于手动/开发人员的应用程序测试创建一些虚拟数据。
我的主数据库播种器的当前代码如下:
class DatabaseSeeder extends Seeder
{
public function run()
{
$this->call([
UserTableSeeder::class,
]);
\App\Models\User::factory(10)->create();
\App\Models\Activity::factory(5)->create();
/* 1. try
$tenFact = \App\Models\Tenant::factory(2)->has(
\App\Models\Project::factory(2)->state(
function (array $attributes, \App\Models\Tenant $tenant) {
return ['tenant_id' => $attributes['id']];
}
)->hasTasks(5)->hasLocation()
)->hasContracts(3)->create();
*/
/* Currently being used: */
\App\Models\Tenant::factory(10)->has(
\App\Models\Project::factory(5)->hasTasks(5)->hasLocation()
)->hasContracts(3)->create();
}
ProjectFactory.php:
class ProjectFactory extends Factory
{
protected $model = Project::class;
public function definition()
{
return [
'name' => 'Projekt: '. $this->faker->name,
'budget' => $this->faker->randomDigitNotNull*1000,
'progress' => $this->faker->randomDigitNotNull*10,
'budget_used' => $this->faker->randomDigitNotNull*50,
//'tenant_id' => Tenant::factory(),
'location_id' => Location::factory()->hasTenant(1),
];
}
}
LocationFactory.php:
class LocationFactory extends Factory
{
protected $model = Location::class;
public function definition()
{
return [
'name' => 'Standort: ' . $this->faker->company,
'street' => $this->faker->streetName,
'house_number' => $this->faker->buildingNumber,
'house_addition' => $this->faker->secondaryAddress,
'zip' => $this->faker->postcode,
'city' => $this->faker->city,
'tenant_id' => Tenant::factory(),
];
}
}
我们的关系是这样的:
Tenant
|-- Project (has: tenant_id, but also has location_id)
| | -- Task (has: project_id)
|-- Locations (has: tenant_id)
|-- Contracts (has: tenant_id)
使用上面命名的 Tenant-Factory 创建数据集时,会发生以下情况:
- Tenant->id 正在传递给 Project(tenant_id) 但是:Tenant->id 没有传递给 Location(这取决于租户 id 但也用于 Project)。
我们如何将 \App\Models\Tenant::factory(10) 的 id 传递给 Project::factory(5)->hasTasks(5)->hasLocation()?
此外,我们确实有问题,即使我们请求 10 个租户,我们也会得到大约 60 个,因为 Location/Project 在它们应该使用现有对象时创建新对象。
class ProjectFactory extends Factory
{
$location_ids = App\Models\Location::pluck('id')->toArray();
protected $model = Project::class;
public function definition()
{
return [
'name' => 'Projekt: '. $this->faker->name,
'budget' => $this->faker->randomDigitNotNull*1000,
'progress' => $this->faker->randomDigitNotNull*10,
'budget_used' => $this->faker->randomDigitNotNull*50,
//'tenant_id' => Tenant::factory(),
'location_id'=> $faker->randomElement($location_ids),
];
}
}
class LocationFactory extends Factory
{
$tenant_ids = App\Models\Tenant::pluck('id')->toArray();
protected $model = Location::class;
public function definition()
{
return [
'name' => 'Standort: ' . $this->faker->company,
'street' => $this->faker->streetName,
'house_number' => $this->faker->buildingNumber,
'house_addition' => $this->faker->secondaryAddress,
'zip' => $this->faker->postcode,
'city' => $this->faker->city,
'tenant_id'=> $faker->randomElement($tenant_ids),
];
}
}
我放弃了使用 Tenant-Factory 的链式使用 - 我最终使用了一些 for-Loop,通过使用 laravels for() 和 state() 方法将相关对象连接到每个用户:
for ($i=0; $i < 10 ; $i++) {
$tenant = \App\Models\Tenant::factory()->hasContracts(3)->create();
for ($j=0; $j < 5; $j++) {
$location = \App\Models\Location::factory(1)->for($tenant)->create();
$project = \App\Models\Project::factory(1)->state([
'location_id' => $location->first()['id'],
'tenant_id' => $tenant['id']])->hasTasks(5)->create();
}
}