RxJava 将 Single<String> 对象转换为 String class
RxJava convert Single<String> object to String class
是否可以将 Single 对象转换为 String class?
单个 <用户> stringSingle = Single.just(User.getName());
字符串 s = "";
s=stringSingle;
如何将 stringSingle 分配给 s 变量?
你可以有这样的东西。
import rx.Single;
import lombok.Getter;
public class TestClass {
public static void main(String[] args) {
Single<User> stringSingle = Single.just(new User("Peter", 9));
final String[] s = new String[1];
//Asynchronous and advisable
stringSingle.subscribe( result -> {
s[0] = result.toString();
});
System.out.println(s[0]);
//Blocking and not very advisible way of getting the value
String s2 = stringSingle.toBlocking().value().toString();
System.out.println(s2);
}
}
//Example of a possible User class to use.
class User{
@Getter
private String name;
@Getter
private int age ;
public User( String nm, int ag){
name = nm;
age = ag;
}
@Override
public String toString(){
return "name " + getName() + " and age " + getAge();
}
}
结果是
name Peter and age 9
name Peter and age 9
是否可以将 Single 对象转换为 String class?
单个 <用户> stringSingle = Single.just(User.getName());
字符串 s = "";
s=stringSingle;
如何将 stringSingle 分配给 s 变量?
你可以有这样的东西。
import rx.Single;
import lombok.Getter;
public class TestClass {
public static void main(String[] args) {
Single<User> stringSingle = Single.just(new User("Peter", 9));
final String[] s = new String[1];
//Asynchronous and advisable
stringSingle.subscribe( result -> {
s[0] = result.toString();
});
System.out.println(s[0]);
//Blocking and not very advisible way of getting the value
String s2 = stringSingle.toBlocking().value().toString();
System.out.println(s2);
}
}
//Example of a possible User class to use.
class User{
@Getter
private String name;
@Getter
private int age ;
public User( String nm, int ag){
name = nm;
age = ag;
}
@Override
public String toString(){
return "name " + getName() + " and age " + getAge();
}
}
结果是
name Peter and age 9
name Peter and age 9