应用新yaml时如何传递参数文件

Question

我正在使用 openshift 4.6。我想将参数传递给 yaml 文件，所以我尝试了下面的代码，但它抛出了一个错误

oc apply -f "./ETCD Backup/etcd_backup_cronjob.yaml" --param master-node = oc get nodes -o name |  grep "master-0" | cut -d'/' -f2

错误：未知标志 --param

Answer 1

您最想使用的是 OpenShift Templates。使用模板，您可以在 YAML 文件中包含变量，然后使用 oc process.

更改它们

因此您的 YAML 将如下所示：

kind: Template
apiVersion: v1
metadata:
  name: my-template
objects:
  - apiVersion: batch/v1beta1
    kind: CronJob
    metadata:
      name: pi
    spec:
      schedule: "*/1 * * * *"  
      concurrencyPolicy: "Replace" 
      startingDeadlineSeconds: 200 
      suspend: true            
      successfulJobsHistoryLimit: 3 
      failedJobsHistoryLimit: 1     
      jobTemplate:             
        spec:
          template:
            metadata:
              labels:          
                 parent: "cronjobpi"
            spec:
              containers:
              - name: pi
                image: perl
                command: ["perl",  "-Mbignum=bpi", "-wle", "print bpi(${{DIGITS}})"]
              restartPolicy: OnFailure 
parameters:
  - name: DIGITS 
    displayName: Number of digits 
    description: Digits to compute
    value: 200 
    required: true

然后你可以像这样使用oc process:

oc process my-template.yml --param=DIGITS=300 | oc apply -f -

应用新yaml时如何传递参数文件

How to pass param file when applying a new yaml

openshift

openshift-4