Ext js 3.4 获取节点

Ext js 3.4 get node

我有带有听众的 TreePanel:

listeners: {
        contextmenu: function(node) {
            if(node === tree.getRootNode())
                contextMenu.items.get(1).setDisabled(true);
            else 
                contextMenu.items.get(1).setDisabled(false);
            contextMenu.show(node.ui.getEl());  
        }}

我有上下文菜单。

var contextMenu = new Ext.menu.Menu({
    items: [{
        text: 'Add',
        icon: './static/ExtJS/images/default/dd/drop-add.gif',
        handler: function(item, checked){}, {
        text: "Remove",
        icon: "./static/ExtJS/images/default/dd/drop-no.gif",
        handler: function(item){
    }}]
});

我怎样才能进入处理程序节点,应该在哪里添加新节点?

只需将节点存储在某处:

contextMenu.activeNode = node;
contextMenu.show();

// In the handler
handler: function(item) {
    var node = item.ownerCt.activeNode
}