Oracle sql 以逗号分隔的旋转值

Question

我有以下输入

ID	LOTYP	PROID	LOCKR
XXXXX	06	01	Y
XXXXX	06	02	X
XXXXX	06	02	S
XXXXX	06	01	R
XXXXX	02	01	Y
XXXXX	02	02	X
XXXXX	02	02	S
XXXXX	02	01	R
YYYYY	06	01	Y
YYYYY	06	02	X
YYYYY	06	02	S
YYYYY	06	01	R
YYYYY	02	01	Y
YYYYY	02	02	X
YYYYY	02	02	S
YYYYY	02	01	R

我想要下面的输出

ID	0201	0202	0601	0602
XXXXX	R, Y	S, X	R, Y	S, X
YYYYY	R, Y	S, X	R, Y	S, X

我可以分别使用 pivot 和 listagg，但我很难将它们组合起来以产生所需的输出。

Answer 1

您可以对 id 和串联 (lotyp||proid) 列的分组结果进行透视，例如

SELECT *
  FROM
  (
    SELECT id,lotyp||proid As title,
           LISTAGG(lockr,',') WITHIN GROUP (ORDER BY lotyp||proid) AS value
      FROM t
     GROUP BY id,lotyp||proid )
 PIVOT (
         MAX(value) FOR title IN ('0201' AS "0201",
                                  '0202' AS "0202",
                                  '0601' AS "0601",
                                  '0602' AS "0602"))   
 ORDER BY id;

ID	0201	0202	0601	0602
XXXXX	R,Y	S,X	R,Y	S,X
YYYYY	R,Y	S,X	R,Y	S,X

Demo

Answer 2

我发现条件聚合比 pivot:

简单多了

SELECT id,
       LISTAGG(CASE WHEN lotyp = '02' AND proid = '01' THEN lockr END, ',') WITHIN GROUP (ORDER BY lockr) as "0201",
       LISTAGG(CASE WHEN lotyp = '02' AND proid = '02' THEN lockr END, ',') WITHIN GROUP (ORDER BY lockr) as "0201",
       LISTAGG(CASE WHEN lotyp = '06' AND proid = '01' THEN lockr END, ',') WITHIN GROUP (ORDER BY lockr) as "0601",
       LISTAGG(CASE WHEN lotyp = '02' AND proid = '01' THEN lockr END, ',') WITHIN GROUP (ORDER BY lockr) as "0601"
FROM t
GROUP BY id ;

没有子查询。只是清楚地做你想做的事情的逻辑。

Oracle sql 以逗号分隔的旋转值

Oracle sql pivoting values separated by commas

sql

oracle

pivot