如何将这种类型的数据解析为Swift中的JSON?
How to parse this type of data to a JSON in Swift?
我调用了一个API来获取一年中的所有假期,结果是Json类型。但我只能像下面那样提取它(它是“项目”的众多元素之一)
"items": [
{
"kind": "calendar#event",
"etag": "\"3235567993214000\"",
"id": "20200101_1814eggq09ims8ge9pine82pclgn49rj41262u9a00oe83po05002i01",
"status": "confirmed",
"htmlLink": "https://www.google.com/calendar/event?eid=MjAyMDAxMDFfMTgxNGVnZ3EwOWltczhnZTlwaW5lODJwY2xnbjQ5cmo0MTI2MnU5YTAwb2U4M3BvMDUwMDJpMDEgZW4udWsjaG9saWRheUB2",
"created": "2021-04-07T08:26:36.000Z",
"updated": "2021-04-07T08:26:36.607Z",
"summary": "New Year's Day",
"creator": {
"email": "en.uk#holiday@group.v.calendar.google.com",
"displayName": "Holidays in United Kingdom",
"self": true
},
"organizer": {
"email": "en.uk#holiday@group.v.calendar.google.com",
"displayName": "Holidays in United Kingdom",
"self": true
},
"start": {
"date": "2020-01-01"
},
"end": {
"date": "2020-01-02"
},
"transparency": "transparent",
"visibility": "public",
"iCalUID": "20200101_1814eggq09ims8ge9pine82pclgn49rj41262u9a00oe83po05002i01@google.com",
"sequence": 0,
"eventType": "default"
},
{
"kind": "calendar#event",
"etag": "\"3235567993214000\"",
"id": "20200412_1814eggq09ims8gd8lgn6t35e8g56tbechgniag063i0ue048064g0g",
"status": "confirmed",
"htmlLink": "https://www.google.com/calendar/event?eid=MjAyMDA0MTJfMTgxNGVnZ3EwOWltczhnZDhsZ242dDM1ZThnNTZ0YmVjaGduaWFnMDYzaTB1ZTA0ODA2NGcwZyBlbi51ayNob2xpZGF5QHY",
"created": "2021-04-07T08:26:36.000Z",
"updated": "2021-04-07T08:26:36.607Z",
"summary": "Easter Sunday",
"creator": {
"email": "en.uk#holiday@group.v.calendar.google.com",
"displayName": "Holidays in United Kingdom",
"self": true
},
"organizer": {
"email": "en.uk#holiday@group.v.calendar.google.com",
"displayName": "Holidays in United Kingdom",
"self": true
},
"start": {
"date": "2020-04-12"
},
"end": {
"date": "2020-04-13"
},
"transparency": "transparent",
"visibility": "public",
"iCalUID": "20200412_1814eggq09ims8gd8lgn6t35e8g56tbechgniag063i0ue048064g0g@google.com",
"sequence": 0,
"eventType": "default"
}
我尝试获取键“start”和键“summary”中的值,但我做不到。
Xcode 告诉我“项目”是 __NSArrayI
类型。
到目前为止我尝试的是创建一个像这样简单的class(只是先尝试使用,所以我没有制作所有变量)
class API_Info {
var kind: String?
var etag: String?
var id: String?
var status: String?
var htmlLink: String?
var created: String?
var updated: String?
var summary: String?
init(items: [String:Any]){
self.kind = items["kind"] as? String
self.etag = items["etag"] as? String
self.id = items["id"] as? String
self.status = items["status"] as? String
self.htmlLink = items["htmlLink"] as? String
self.created = items["created"] as? String
self.updated = items["updated"] as? String
self.summary = items["summary"] as? String
}
}
我这样解析:
guard let items = json!["items"]! as? [API_Info] else{
print("null")
return
}
这样else语句就是运行.
我做错了什么,我怎样才能得到我想要的数据?
提前致谢。
Codable
是这里的解决方案。下面是我使用的结构而不是你的 class
struct ApiInfo: Codable {
let kind: String
let etag: String
let id: String
let status: String
let htmlLink: String
let created: Date
let updated: Date
let summary: String
}
然后我创建了一个根类型来保存数组
struct Result: Codable {
let items: [ApiInfo]
}
然后解码
let formatter = DateFormatter()
formatter.dateFormat = "yyyy-MM-dd'T'HH:mm:ss.SSSZ"
let decoder = JSONDecoder()
decoder.dateDecodingStrategy = .formatted(formatter)
do {
let result = try decoder.decode(Result.self, from: data)
print(result.items)
} catch {
print(error)
}
请注意,数据值被解码为 Date
个对象。
您可以选择跳过根类型并解码为字典
do {
let items = try decoder.decode([String: [ApiInfo]].self, from: data)
if let values = items["items"] {
print(values)
}
} catch {
print(error)
}
我调用了一个API来获取一年中的所有假期,结果是Json类型。但我只能像下面那样提取它(它是“项目”的众多元素之一)
"items": [
{
"kind": "calendar#event",
"etag": "\"3235567993214000\"",
"id": "20200101_1814eggq09ims8ge9pine82pclgn49rj41262u9a00oe83po05002i01",
"status": "confirmed",
"htmlLink": "https://www.google.com/calendar/event?eid=MjAyMDAxMDFfMTgxNGVnZ3EwOWltczhnZTlwaW5lODJwY2xnbjQ5cmo0MTI2MnU5YTAwb2U4M3BvMDUwMDJpMDEgZW4udWsjaG9saWRheUB2",
"created": "2021-04-07T08:26:36.000Z",
"updated": "2021-04-07T08:26:36.607Z",
"summary": "New Year's Day",
"creator": {
"email": "en.uk#holiday@group.v.calendar.google.com",
"displayName": "Holidays in United Kingdom",
"self": true
},
"organizer": {
"email": "en.uk#holiday@group.v.calendar.google.com",
"displayName": "Holidays in United Kingdom",
"self": true
},
"start": {
"date": "2020-01-01"
},
"end": {
"date": "2020-01-02"
},
"transparency": "transparent",
"visibility": "public",
"iCalUID": "20200101_1814eggq09ims8ge9pine82pclgn49rj41262u9a00oe83po05002i01@google.com",
"sequence": 0,
"eventType": "default"
},
{
"kind": "calendar#event",
"etag": "\"3235567993214000\"",
"id": "20200412_1814eggq09ims8gd8lgn6t35e8g56tbechgniag063i0ue048064g0g",
"status": "confirmed",
"htmlLink": "https://www.google.com/calendar/event?eid=MjAyMDA0MTJfMTgxNGVnZ3EwOWltczhnZDhsZ242dDM1ZThnNTZ0YmVjaGduaWFnMDYzaTB1ZTA0ODA2NGcwZyBlbi51ayNob2xpZGF5QHY",
"created": "2021-04-07T08:26:36.000Z",
"updated": "2021-04-07T08:26:36.607Z",
"summary": "Easter Sunday",
"creator": {
"email": "en.uk#holiday@group.v.calendar.google.com",
"displayName": "Holidays in United Kingdom",
"self": true
},
"organizer": {
"email": "en.uk#holiday@group.v.calendar.google.com",
"displayName": "Holidays in United Kingdom",
"self": true
},
"start": {
"date": "2020-04-12"
},
"end": {
"date": "2020-04-13"
},
"transparency": "transparent",
"visibility": "public",
"iCalUID": "20200412_1814eggq09ims8gd8lgn6t35e8g56tbechgniag063i0ue048064g0g@google.com",
"sequence": 0,
"eventType": "default"
}
我尝试获取键“start”和键“summary”中的值,但我做不到。
Xcode 告诉我“项目”是 __NSArrayI
类型。
到目前为止我尝试的是创建一个像这样简单的class(只是先尝试使用,所以我没有制作所有变量)
class API_Info {
var kind: String?
var etag: String?
var id: String?
var status: String?
var htmlLink: String?
var created: String?
var updated: String?
var summary: String?
init(items: [String:Any]){
self.kind = items["kind"] as? String
self.etag = items["etag"] as? String
self.id = items["id"] as? String
self.status = items["status"] as? String
self.htmlLink = items["htmlLink"] as? String
self.created = items["created"] as? String
self.updated = items["updated"] as? String
self.summary = items["summary"] as? String
}
}
我这样解析:
guard let items = json!["items"]! as? [API_Info] else{
print("null")
return
}
这样else语句就是运行.
我做错了什么,我怎样才能得到我想要的数据?
提前致谢。
Codable
是这里的解决方案。下面是我使用的结构而不是你的 class
struct ApiInfo: Codable {
let kind: String
let etag: String
let id: String
let status: String
let htmlLink: String
let created: Date
let updated: Date
let summary: String
}
然后我创建了一个根类型来保存数组
struct Result: Codable {
let items: [ApiInfo]
}
然后解码
let formatter = DateFormatter()
formatter.dateFormat = "yyyy-MM-dd'T'HH:mm:ss.SSSZ"
let decoder = JSONDecoder()
decoder.dateDecodingStrategy = .formatted(formatter)
do {
let result = try decoder.decode(Result.self, from: data)
print(result.items)
} catch {
print(error)
}
请注意,数据值被解码为 Date
个对象。
您可以选择跳过根类型并解码为字典
do {
let items = try decoder.decode([String: [ApiInfo]].self, from: data)
if let values = items["items"] {
print(values)
}
} catch {
print(error)
}