如何使用 C 正则表达式提取子匹配项

Question

我已经使 GNU 正则表达式库的工作方式与我大约 2 年前写的广泛文本处理算法中所宣传的完全一样，但不幸的是，该平台已经消失，我不知道它的版本是旧版本还是新版本参考如下。

代码如下：

// GNU libc version: 2.28
// gcc (Ubuntu 7.5.0-3ubuntu1~18.04) 7.5.0

#include <stdio.h>
#include <regex.h>

int main() {

    regex_t preg;
    char str[] = "dave";
    char regex[] = "\(.\)ave";

    // flag REG_EXTENDED with unescaped parens in the r.e. doesn't fix anything
    int ret, cflags = REG_ICASE;
    
    // the elements of unused pmatches used to be set to -1 by regexec, but no longer. a clue perhaps.

    regmatch_t pmatch[2] = {{-1,-1},{-1,-1}};

    ret = regcomp(&preg, regex, cflags);
    if (ret) {
        puts("regcomp fail");
        return ret;
    }
    else
        // preg.re_nsub contains the correct number of groups that regcomp recognized in the r.e. Tests succeeded for 0, 1, 2, and 3 groups.
        printf("regcomp ok; re_nsub=%zu\n", preg.re_nsub);

    ret = regexec(&preg, str, 1, pmatch, 0);

    if(ret)
        puts("no match");
    else {
        printf("match offsets are %d %d\n", pmatch[0].rm_so, pmatch[0].rm_eo);
        printf("match[0]=%*s<\n", pmatch[0].rm_eo, &str[pmatch[0].rm_so]);

        printf("submatch offsets are %d %d\n", pmatch[1].rm_so, pmatch[1].rm_eo);
        if(pmatch[1].rm_so != -1)
            printf("match[1]=%*s<\n", pmatch[1].rm_eo, &str[pmatch[1].rm_so]);
    }
    return 0;
}
/*
output:
regcomp ok; re_nsub=1
match offsets are 0 4
match[0]=dave<
submatch offsets are -1 -1
*/

Answer 1

您没有获得第一个捕获组的偏移量的问题是您将 1 作为第三个 size_t __nmatch 参数传递给 regexec。

1 值应更改为 2，因为每当 \(.\)ave 正则表达式匹配时都会有两个组：第 0 组将举行整个比赛，第 1 组将举行整个比赛首先捕获组值。

所以，你需要使用

ret = regexec(&preg, str, 2, pmatch, 0);
//                       ^^^

此外，要打印第 1 组值，您可以使用

if(pmatch[1].rm_so != -1) {
    printf("match[1]=%.*s<\n", pmatch[1].rm_eo, &str[pmatch[1].rm_so]);
}

参见this C demo：

#include <stdio.h>
#include <regex.h>
#include <string.h>

int main() {

    regex_t preg;
    char str[] = "dave";
    char regex[] = "\(.\)ave";

    // flag REG_EXTENDED with unescaped parens in the r.e. doesn't fix anything
    int ret, cflags = REG_ICASE;
    
    // the elements of unused pmatches used to be set to -1 by regexec, but no longer. a clue perhaps.

    regmatch_t pmatch[2] = {{-1,-1},{-1,-1}};

    ret = regcomp(&preg, regex, cflags);
    if (ret) {
        puts("regcomp fail");
        return ret;
    }
    else
        // preg.re_nsub contains the correct number of groups that regcomp recognized in the r.e. Tests succeeded for 0, 1, 2, and 3 groups.
        printf("regcomp ok; re_nsub=%zu\n", preg.re_nsub);

    ret = regexec(&preg, str, 2, pmatch, 0); // 1 changed to 2 as there is Group 0 (whole match) and Group 1 (for the first capturing group)

    if(ret)
        puts("no match");
    else {
        printf("match offsets are %d %d\n", pmatch[0].rm_so, pmatch[0].rm_eo);
        printf("match[0]=%*s<\n", pmatch[0].rm_eo, &str[pmatch[0].rm_so]);

        printf("submatch offsets are %d %d\n", pmatch[1].rm_so, pmatch[1].rm_eo);
        if(pmatch[1].rm_so != -1) {
            printf("match[1]=%.*s<\n", pmatch[1].rm_eo, &str[pmatch[1].rm_so]);
        }
    }
    return 0;
}
/*
regcomp ok; re_nsub=1
match offsets are 0 4
match[0]=dave<
submatch offsets are 0 1
match[1]=d<
*/

如何使用 C 正则表达式提取子匹配项

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