无法使用 Pulumi 构建 dockerfile
Can't build dockerfile with Pulumi
我正在尝试使用 Pulumi 构建一个 docker 文件。我有以下 Pulumi 代码
func main() {
pulumi.Run(func(ctx *pulumi.Context) error {
imageName := "server"
_, err = docker.NewImage(ctx, imageName, &docker.ImageArgs{
ImageName: pulumi.Sprintf("gcr.io/gadic-310112/%s:latest", imageName),
SkipPush: pulumi.Bool(true),
Build: &docker.DockerBuildArgs{
Dockerfile: pulumi.String("Dockerfile"),
},
})
if err != nil {
return err
}
}
}
但是,当我 运行 pulumi preview
我得到以下错误:
Diagnostics:
pulumi:pulumi:Stack (server-prod):
error: program failed: docker build -f Dockerfile . -t gcr.io/gadic-310112/server:latest failed with error: exit status 1
exit status 1
error: an unhandled error occurred: program exited with non-zero exit code: 1
docker:image:Image (server):
error: #1 [internal] load build definition from Dockerfile
#1 sha256:921a08a3c227abd8c3811effc689fa5319db237c32a4adf2b255007a51af9ef8
#1 transferring dockerfile: 2B 0.0s done
#1 DONE 0.0s
failed to solve with frontend dockerfile.v0: failed to read dockerfile: open /var/lib/docker/tmp/buildkit-mount052159980/Dockerfile: no such file or directory
有趣的是,Pulumi 似乎是 运行宁 docker build -f Dockerfile . -t gcr.io/gadic-310112/server:latest
幕后黑手。当我从我的终端 运行 它成功时没有任何错误。
❯❯❯ docker build -f Dockerfile . -t gcr.io/gadic-310112/server:latest
[+] Building 11.3s (16/18)
=> [internal] load build definition from Dockerfile 0.0s
=> => transferring dockerfile: 1.87kB 0.0s
=> [internal] load .dockerignore 0.0s
=> => transferring context: 34B 0.0s
....
看来 Pulumi 使用的工作目录可能与调用它的地方不同。那可能吗?还有其他可能发生的事情吗?
我注意到,如果我不在 DockerBuildArgs
中包含 Dockerfile
,那么 pulumi 生成的命令是 docker build -f . -t gcr.io/gadic-310112/server:latest
,这绝对是不正确的。如果我在本地执行该命令,我会得到以下信息:
❮❮❮ docker build -f . -t gcr.io/gadic-310112/server:latest
"docker build" requires exactly 1 argument.
See 'docker build --help'.
Usage: docker build [OPTIONS] PATH | URL | -
Build an image from a Dockerfile
编辑:我还尝试将绝对路径传递到包含我的 Dockerfile 的文件夹,作为 BuildArgs
的 Context
Build: &docker.DockerBuildArgs{
Dockerfile: pulumi.String("Dockerfile"),
Context: pulumi.String("/Users/paymahn/gadic/server"),
},
这仍然会出现与以前相同的错误,即使底层 docker build
命令具有绝对路径:
Diagnostics:
docker:image:Image (server):
error: #1 [internal] load build definition from Dockerfile
#1 sha256:16f11ab26c775f06385c0fde07864ed70b428d13662aa2be42823751fb5143f4
#1 transferring dockerfile: 2B 0.0s done
#1 DONE 0.1s
failed to solve with frontend dockerfile.v0: failed to read dockerfile: open /var/lib/docker/tmp/buildkit-mount684750851/Dockerfile: no such file or directory
pulumi:pulumi:Stack (server-prod):
error: program failed: docker build -f Dockerfile /Users/paymahn/gadic/server -t gcr.io/gadic-310112/server:latest failed with error: exit status 1
exit status 1
error: an unhandled error occurred: program exited with non-zero exit code: 1
编辑 2:这是我的文件布局
/Users/paymahn/gadic/server/
infra/
main.go # this is the go program that pulumi runs
src/ # this is where the source code for my server lives
Dockerfile
Pulumi.yaml
Pulumi.prod.yaml # the pulumi stack config
go.sum
go.mod
.git/ # this is the root of my git repository
您的 Pulumi 项目构建在您的 infra
目录中,而不是您的 Pulumi.yaml
所在的文件夹中。
Pulumi 提供者需要使用 docker 构建上下文了解 Dockerfile
的路径(有关这些 here 的更多信息)
添加上下文应该可以解决这个问题:
func main() {
pulumi.Run(func(ctx *pulumi.Context) error {
imageName := "server"
_, err = docker.NewImage(ctx, imageName, &docker.ImageArgs{
ImageName: pulumi.Sprintf("gcr.io/gadic-310112/%s:latest", imageName),
SkipPush: pulumi.Bool(true),
Build: &docker.DockerBuildArgs{
Dockerfile: pulumi.String("Dockerfile"),
Context: "../", # note I'm adding the context here
},
})
if err != nil {
return err
}
}
}
我正在尝试使用 Pulumi 构建一个 docker 文件。我有以下 Pulumi 代码
func main() {
pulumi.Run(func(ctx *pulumi.Context) error {
imageName := "server"
_, err = docker.NewImage(ctx, imageName, &docker.ImageArgs{
ImageName: pulumi.Sprintf("gcr.io/gadic-310112/%s:latest", imageName),
SkipPush: pulumi.Bool(true),
Build: &docker.DockerBuildArgs{
Dockerfile: pulumi.String("Dockerfile"),
},
})
if err != nil {
return err
}
}
}
但是,当我 运行 pulumi preview
我得到以下错误:
Diagnostics:
pulumi:pulumi:Stack (server-prod):
error: program failed: docker build -f Dockerfile . -t gcr.io/gadic-310112/server:latest failed with error: exit status 1
exit status 1
error: an unhandled error occurred: program exited with non-zero exit code: 1
docker:image:Image (server):
error: #1 [internal] load build definition from Dockerfile
#1 sha256:921a08a3c227abd8c3811effc689fa5319db237c32a4adf2b255007a51af9ef8
#1 transferring dockerfile: 2B 0.0s done
#1 DONE 0.0s
failed to solve with frontend dockerfile.v0: failed to read dockerfile: open /var/lib/docker/tmp/buildkit-mount052159980/Dockerfile: no such file or directory
有趣的是,Pulumi 似乎是 运行宁 docker build -f Dockerfile . -t gcr.io/gadic-310112/server:latest
幕后黑手。当我从我的终端 运行 它成功时没有任何错误。
❯❯❯ docker build -f Dockerfile . -t gcr.io/gadic-310112/server:latest
[+] Building 11.3s (16/18)
=> [internal] load build definition from Dockerfile 0.0s
=> => transferring dockerfile: 1.87kB 0.0s
=> [internal] load .dockerignore 0.0s
=> => transferring context: 34B 0.0s
....
看来 Pulumi 使用的工作目录可能与调用它的地方不同。那可能吗?还有其他可能发生的事情吗?
我注意到,如果我不在 DockerBuildArgs
中包含 Dockerfile
,那么 pulumi 生成的命令是 docker build -f . -t gcr.io/gadic-310112/server:latest
,这绝对是不正确的。如果我在本地执行该命令,我会得到以下信息:
❮❮❮ docker build -f . -t gcr.io/gadic-310112/server:latest
"docker build" requires exactly 1 argument.
See 'docker build --help'.
Usage: docker build [OPTIONS] PATH | URL | -
Build an image from a Dockerfile
编辑:我还尝试将绝对路径传递到包含我的 Dockerfile 的文件夹,作为 BuildArgs
Context
Build: &docker.DockerBuildArgs{
Dockerfile: pulumi.String("Dockerfile"),
Context: pulumi.String("/Users/paymahn/gadic/server"),
},
这仍然会出现与以前相同的错误,即使底层 docker build
命令具有绝对路径:
Diagnostics:
docker:image:Image (server):
error: #1 [internal] load build definition from Dockerfile
#1 sha256:16f11ab26c775f06385c0fde07864ed70b428d13662aa2be42823751fb5143f4
#1 transferring dockerfile: 2B 0.0s done
#1 DONE 0.1s
failed to solve with frontend dockerfile.v0: failed to read dockerfile: open /var/lib/docker/tmp/buildkit-mount684750851/Dockerfile: no such file or directory
pulumi:pulumi:Stack (server-prod):
error: program failed: docker build -f Dockerfile /Users/paymahn/gadic/server -t gcr.io/gadic-310112/server:latest failed with error: exit status 1
exit status 1
error: an unhandled error occurred: program exited with non-zero exit code: 1
编辑 2:这是我的文件布局
/Users/paymahn/gadic/server/
infra/
main.go # this is the go program that pulumi runs
src/ # this is where the source code for my server lives
Dockerfile
Pulumi.yaml
Pulumi.prod.yaml # the pulumi stack config
go.sum
go.mod
.git/ # this is the root of my git repository
您的 Pulumi 项目构建在您的 infra
目录中,而不是您的 Pulumi.yaml
所在的文件夹中。
Pulumi 提供者需要使用 docker 构建上下文了解 Dockerfile
的路径(有关这些 here 的更多信息)
添加上下文应该可以解决这个问题:
func main() {
pulumi.Run(func(ctx *pulumi.Context) error {
imageName := "server"
_, err = docker.NewImage(ctx, imageName, &docker.ImageArgs{
ImageName: pulumi.Sprintf("gcr.io/gadic-310112/%s:latest", imageName),
SkipPush: pulumi.Bool(true),
Build: &docker.DockerBuildArgs{
Dockerfile: pulumi.String("Dockerfile"),
Context: "../", # note I'm adding the context here
},
})
if err != nil {
return err
}
}
}