pynput.keyboard 按键无响应时终止程序

Question

我这里有这段代码，我想要的是每 5 秒输入一次“potato”的代码。我还想要一个“退出”命令，我想要它以便在我按下 = 时它会停止程序。然而，代码不仅不起作用，而且还在它后面键入“=” types/enters “potato”。有人可以帮忙吗？谢谢

from pynput.keyboard import Key, Controller
import time

keyboard = Controller()
time.sleep(3)

while True:
  keyboard.type('potato')
  keyboard.press(Key.enter)
  keyboard.release(Key.enter)
  if keyboard.type('asdf'):
    quit()
  time.sleep(5)

P.S。没有错误或任何东西

Answer 1

这里最明显的答案是在 if 语句中将“asdf”更改为“=”，但如果这不能解决问题，您可以添加一个侦听器来检测按键。

from pynput import keyboard, Key, Controller
import time

# set your termination key here
cut_key = "="

# check if key pressed is cut_key, if so, quit
def on_press(key):
    try:
        if key.char == cut_key:
            quit()
    except AttributeError:
        if key == cut_key:
            quit()

# non-blocking listener
listener = keyboard.Listener(
    on_press=on_press)
listener.start()

keyboard = Controller()
time.sleep(3)

while True:
    keyboard.type('potato')
    keyboard.press(Key.enter)
    keyboard.release(Key.enter)
    time.sleep(5)

我没有测试这段代码，如果它不起作用请评论。 https://pynput.readthedocs.io/en/latest/keyboard.html

pynput.keyboard 按键无响应时终止程序

pynput.keyboard terminate program when key is pressed not responding

keyboard

pynput