Ramda - 从多个对象的嵌套数组中获取 ID
Ramda - get ids from nested array of multiple objects
我正在尝试获取存储在对象内部数组中的 outgoingNodes
ID,如下例所示,但我不知道从哪里开始...:[=12=]
const nodes = {
"818": {
"id": "818",
"index": 1,
"outgoingNodes": [
"819"
],
},
"819": {
"id": "819",
"outgoingNodes": [
"820",
"821"
],
}
}
我想得到一组 ID 作为结果。任何帮助将不胜感激。
获取值(子对象),提取 outgoingNodes
数组,并展平为单个数组:
const { pipe, values, pluck, flatten } = R
const fn = pipe(
values,
pluck('outgoingNodes'),
flatten
)
const nodes = {"818":{"id":"818","index":1,"outgoingNodes":["819"]},"819":{"id":"819","outgoingNodes":["820","821"]}}
const result = fn(nodes)
console.log(result)
<script src="https://cdnjs.cloudflare.com/ajax/libs/ramda/0.27.1/ramda.min.js" integrity="sha512-rZHvUXcc1zWKsxm7rJ8lVQuIr1oOmm7cShlvpV0gWf0RvbcJN6x96al/Rp2L2BI4a4ZkT2/YfVe/8YvB2UHzQw==" crossorigin="anonymous"></script>
另一种选择是结合获取 outgoingNodes
数组,并使用 R.chain 和 R.prop 展平为单个数组:
const { pipe, values, chain, prop } = R
const fn = pipe(
values,
chain(prop('outgoingNodes')),
)
const nodes = {"818":{"id":"818","index":1,"outgoingNodes":["819"]},"819":{"id":"819","outgoingNodes":["820","821"]}}
const result = fn(nodes)
console.log(result)
<script src="https://cdnjs.cloudflare.com/ajax/libs/ramda/0.27.1/ramda.min.js" integrity="sha512-rZHvUXcc1zWKsxm7rJ8lVQuIr1oOmm7cShlvpV0gWf0RvbcJN6x96al/Rp2L2BI4a4ZkT2/YfVe/8YvB2UHzQw==" crossorigin="anonymous"></script>
我正在尝试获取存储在对象内部数组中的 outgoingNodes
ID,如下例所示,但我不知道从哪里开始...:[=12=]
const nodes = {
"818": {
"id": "818",
"index": 1,
"outgoingNodes": [
"819"
],
},
"819": {
"id": "819",
"outgoingNodes": [
"820",
"821"
],
}
}
我想得到一组 ID 作为结果。任何帮助将不胜感激。
获取值(子对象),提取 outgoingNodes
数组,并展平为单个数组:
const { pipe, values, pluck, flatten } = R
const fn = pipe(
values,
pluck('outgoingNodes'),
flatten
)
const nodes = {"818":{"id":"818","index":1,"outgoingNodes":["819"]},"819":{"id":"819","outgoingNodes":["820","821"]}}
const result = fn(nodes)
console.log(result)
<script src="https://cdnjs.cloudflare.com/ajax/libs/ramda/0.27.1/ramda.min.js" integrity="sha512-rZHvUXcc1zWKsxm7rJ8lVQuIr1oOmm7cShlvpV0gWf0RvbcJN6x96al/Rp2L2BI4a4ZkT2/YfVe/8YvB2UHzQw==" crossorigin="anonymous"></script>
另一种选择是结合获取 outgoingNodes
数组,并使用 R.chain 和 R.prop 展平为单个数组:
const { pipe, values, chain, prop } = R
const fn = pipe(
values,
chain(prop('outgoingNodes')),
)
const nodes = {"818":{"id":"818","index":1,"outgoingNodes":["819"]},"819":{"id":"819","outgoingNodes":["820","821"]}}
const result = fn(nodes)
console.log(result)
<script src="https://cdnjs.cloudflare.com/ajax/libs/ramda/0.27.1/ramda.min.js" integrity="sha512-rZHvUXcc1zWKsxm7rJ8lVQuIr1oOmm7cShlvpV0gWf0RvbcJN6x96al/Rp2L2BI4a4ZkT2/YfVe/8YvB2UHzQw==" crossorigin="anonymous"></script>