将行转换为列并使用 group by 求和

Question

我有一个包含 ID、WorkingDate 和 AmountReceived 列的 table，其中数据显示为

ID    WorkingDate     AmountReceived
-------------------------------------
1     13/April/2021   201999.01 
2     14/Arpil/2021     1099.02

现在，我想表现得像

13/April/2021      14/April/2021    15/April/2021      
--------------------------------------------------
201999.01          1099.02          102.09

我试过了

select AmountReceived, WorkingDate
from Orders o

select distinct o.WorkingDate, sum(AmountReceived) over (partition by WorkingDate) as total 
from Orders o
group by WorkingDate, AmountReceived

但它会引发聚合错误。

Answer 1

使用PIVOT运算符，可以实现你想要的

 select *
 from
 (
    select o.WorkingDate, o.AmountReceived
    from   Orders o
 ) o
 pivot
 (
     sum(AmountReceived)
     for WorkingDate in ([2021-04-13], [2021-04-14], [2021-04-15])
 ) p

将行转换为列并使用 group by 求和

Convert rows to columns and sum with group by

sql

tsql

sql-server

stored-procedures

sql-server-2008