如何获得每一行的总和?
How to get the sum for each row?
我想查找并显示具有最大总和的行号并显示行值,这是示例 input/output:
问题是每次最大和都是第三行如何解决这些问题
int [][] scores = new int[4][3];
for (int i=0; i<scores.length; i++)
{
System.out.print("Enter values for row "+i+": ");
for (int j=0; j<scores[i].length;j++)
scores[i][j] = kbd.nextInt();
}
int sum, sumMax, ii=0;
for (int i=0; i<scores.length; i++)
{
sum =0; sumMax = 0; ii=0;
for (int j=0; j<scores[i].length;j++)
{
sum += scores[i][j];
if (sum>sumMax)
{
sumMax = sum;
ii = i;
}
}
}
System.out.println("Row "+ii+" has the maximum sum");
System.out.print("Row "+ii+" has the following values: ");
for (int j = 0; j < 3; j++)
System.out.print(scores[ii][j] + " ");
要打印特定行,只需要一个循环
System.out.print("Row " + ii + " has the following values: ");
for (int j = 0; j < 3; j++)
System.out.print(scores[ii][j] + " ");
或 Arrays.toString
System.out.println("Row " + ii + " has the following values: " + Arrays.toString(scores[ii]));
另外你的查找最大值代码是错误的,当你将每一行的ii
和sumMax
重置为0时,最大值只能是最后一个行,您需要沿行跟踪这 2 个。仅在计算行的总和后才使用 if
,无需在每一行的每个弓上进行测试
int sum, sumMax = Integer.MIN_VALUE, ii = 0;
for (int i = 0; i < scores.length; i++) {
sum = 0;
for (int j = 0; j < scores[i].length; j++) {
sum += scores[i][j];
}
if (sum > sumMax) {
sumMax = sum;
ii = i;
}
}
您可以在从扫描仪获取输入的同时添加行,并将它们存储在数组中。然后你可以在 sums 数组中搜索最大值:
import java.util.Scanner;
public class Example {
public static void main(String[] args) {
Scanner kbd = new Scanner(System.in);
int[][] scores = new int[4][3];
int[] rowSums = new int[4];
for (int i = 0; i < scores.length; i++) {
System.out.print("Enter values for row " + i + ": ");
for (int j = 0; j < scores[i].length; j++){
scores[i][j] = kbd.nextInt();
rowSums[i] += scores[i][j];
}
}
int index = 0;
int maxSum = rowSums[index];
for(int i = 1; i < rowSums.length; i++){
if(rowSums[i] > maxSum){
maxSum = rowSums[i];
index = i;
}
}
System.out.println("Row "+index+" has the maximum sum");
System.out.print("Row "+index+" has the following values: ");
for(int i = 0; i < scores[index].length; i++){
System.out.print(scores[index][i] + " ");
}
}
}
我想查找并显示具有最大总和的行号并显示行值,这是示例 input/output:
问题是每次最大和都是第三行如何解决这些问题
int [][] scores = new int[4][3];
for (int i=0; i<scores.length; i++)
{
System.out.print("Enter values for row "+i+": ");
for (int j=0; j<scores[i].length;j++)
scores[i][j] = kbd.nextInt();
}
int sum, sumMax, ii=0;
for (int i=0; i<scores.length; i++)
{
sum =0; sumMax = 0; ii=0;
for (int j=0; j<scores[i].length;j++)
{
sum += scores[i][j];
if (sum>sumMax)
{
sumMax = sum;
ii = i;
}
}
}
System.out.println("Row "+ii+" has the maximum sum");
System.out.print("Row "+ii+" has the following values: ");
for (int j = 0; j < 3; j++)
System.out.print(scores[ii][j] + " ");
要打印特定行,只需要一个循环
System.out.print("Row " + ii + " has the following values: ");
for (int j = 0; j < 3; j++)
System.out.print(scores[ii][j] + " ");
或 Arrays.toString
System.out.println("Row " + ii + " has the following values: " + Arrays.toString(scores[ii]));
另外你的查找最大值代码是错误的,当你将每一行的ii
和sumMax
重置为0时,最大值只能是最后一个行,您需要沿行跟踪这 2 个。仅在计算行的总和后才使用 if
,无需在每一行的每个弓上进行测试
int sum, sumMax = Integer.MIN_VALUE, ii = 0;
for (int i = 0; i < scores.length; i++) {
sum = 0;
for (int j = 0; j < scores[i].length; j++) {
sum += scores[i][j];
}
if (sum > sumMax) {
sumMax = sum;
ii = i;
}
}
您可以在从扫描仪获取输入的同时添加行,并将它们存储在数组中。然后你可以在 sums 数组中搜索最大值:
import java.util.Scanner;
public class Example {
public static void main(String[] args) {
Scanner kbd = new Scanner(System.in);
int[][] scores = new int[4][3];
int[] rowSums = new int[4];
for (int i = 0; i < scores.length; i++) {
System.out.print("Enter values for row " + i + ": ");
for (int j = 0; j < scores[i].length; j++){
scores[i][j] = kbd.nextInt();
rowSums[i] += scores[i][j];
}
}
int index = 0;
int maxSum = rowSums[index];
for(int i = 1; i < rowSums.length; i++){
if(rowSums[i] > maxSum){
maxSum = rowSums[i];
index = i;
}
}
System.out.println("Row "+index+" has the maximum sum");
System.out.print("Row "+index+" has the following values: ");
for(int i = 0; i < scores[index].length; i++){
System.out.print(scores[index][i] + " ");
}
}
}