使用 Rest Assured response.jsonPath().getObject() returns 进行序列化 null

Question

我有一个 API 返回 JSON 看起来像这样

{"listings":[
 {
    "albumId": 1,
    "id": 1,
    "title": "accusamus beatae ad facilis cum similique qui sunt",
    "url": "https://via.placeholder.com/600/92c952",
    "thumbnailUrl": "https://via.placeholder.com/150/92c952"
  },
  {
    "albumId": 1,
    "id": 2,
    "title": "reprehenderit est deserunt velit ipsam",
    "url": "https://via.placeholder.com/600/771796",
    "thumbnailUrl": "https://via.placeholder.com/150/771796"
  },
  {
    "albumId": 1,
    "id": 3,
    "title": "officia porro iure quia iusto qui ipsa ut modi",
    "url": "https://via.placeholder.com/600/24f355",
    "thumbnailUrl": "https://via.placeholder.com/150/24f355"
  },
  {
    "albumId": 1,
    "id": 4,
    "title": "culpa odio esse rerum omnis laboriosam voluptate repudiandae",
    "url": "https://via.placeholder.com/600/d32776",
    "thumbnailUrl": "https://via.placeholder.com/150/d32776"
  },
  {
    "albumId": 1,
    "id": 5,
    "title": "natus nisi omnis corporis facere molestiae rerum in",
    "url": "https://via.placeholder.com/600/f66b97",
    "thumbnailUrl": "https://via.placeholder.com/150/f66b97"
  },
]}

我想将 JSON 序列化到我的 MyObject class。我只需要 2 个变量，所以我将忽略其他变量。

import com.fasterxml.jackson.annotation.JsonIgnoreProperties;

@JsonIgnoreProperties(ignoreUnknown=true)
public class MyObject {

    private String title;
    private String url;

    // Getters and Setters here
}

我的测试运行器看起来像这样

public class MyTest {

  @Test
  public void runTest() {

    // Usual Rest-Assured GET request here

    Response response = request
      .request(Method.GET);


    List < MyObject > objects = Arrays.asList(response.jsonPath().getObject("listings", MyObject[].class));

    String testOneTitle = response.jsonPath().get("listings[0].title");
    System.out.println("testOneTitle " + testOneTitle); // OK - Returns String of the title

    System.out.println("Size " + objects.size()); // OK -Returns the size of the List

    for (int z = 0; z < 3; z++) {
      System.out.println("Title " + objects.get(z).getTitle()); // NOK - This returns null 
    }
  }
}

Title null
Title null
Title null

我不知道为什么它 returns 无效。

我怀疑此方法没有正确序列化 JSON？

List < MyObject > objects = Arrays.asList(response.jsonPath().getObject("listings", MyObject[].class));

知道为什么吗？

从讨论中学习，我猜 Rest-Assured 使用第 3 方库来序列化 JSON ？不确定，但我通过添加依赖项

遵循关于 link 的建议

// https://mvnrepository.com/artifact/com.fasterxml.jackson.core/jackson-databind
implementation group: 'com.fasterxml.jackson.core', name: 'jackson-databind', version: '2.12.3'

Answer 1

我并没有真正详细地回答这个问题，因为我了解上下文，看来问题出在 POJO 上。这是我在本地机器上尝试过的东西，我能够得到预期的

@JsonIgnoreProperties(ignoreUnknown = true)
public static class Listing {

    @JsonProperty("listings")
    public List<Listing> listings = null;
    @JsonProperty("title")
    public String title;
    @JsonProperty("url")
    public String url;
    
    // Getters and Setters here

}

public static void main(String[] args) {

    List<Listing> res = RestAssured.given().when().get("http://localhost:8080/stack").then().extract()
            .response().as(Listing.class).getListings();

    for (int z = 0; z < 5; z++) {
        System.out.println("Title " + res.get(z).getTitle());
    }

}

使用 Rest Assured response.jsonPath().getObject() returns 进行序列化 null

Serializing using Rest Assured response.jsonPath().getObject() returns null

java

jackson

rest-assured

rest-assured-jsonpath