如何使用 Python 从 ActiveMQ 队列中删除消息？

Question

我有一个 ActiveMQ 队列，其中有几条消息是使用持久设置为 true 发送的。当我在 Python 中创建一个订阅者来读取队列时，我得到了队列中的所有消息。下次我打开订阅者时，我会收到所有相同的消息。我调整了写入队列的代码以将 persistent 设置为 false，但消息仍保留在队列中。我是否忘记发送确认？

代码是使用 Python 2.7 编写的，因为我们的客户正在使用它。我很想升级它们，但我没有时间。

这是读取队列的脚本：

import socket
import threading
import xml.etree.ElementTree as etree
from xml.dom import minidom  # for pretty printing
# import SampleXML
import sys
import os
import math
import time
from time import monotonic
import string
import stomp # for queue support
import platform


class ConnectionListener(stomp.ConnectionListener):
    def __init__(self, connection):
        self.connection = connection
        print ("Listener created")

    def on_message(self, message):
        print ("Received message with body ") + message.body

class Reader:
    def __init__(self):
        pass
    
    def ConnectToQueue(self):
        #For Production
        user = os.getenv("ACTIVEMQ_USER") or "worthington"
        #user = os.getenv("ACTIVEMQ_USER") or "worthington_test"
        password = os.getenv("ACTIVEMQ_PASSWORD") or "level3"
        host = os.getenv("ACTIVEMQ_HOST") or "localhost"
        port = os.getenv("ACTIVEMQ_PORT") or 61613
        # destination = sys.argv[1:2] or ["/topic/event"]
        # destination = destination[0]
        dest = "from_entec_test"
        #For Production
        # dest = "from_entec"

        try:
            conn = stomp.Connection10(host_and_ports = [(host, port)])
            conn.set_listener('message', ConnectionListener(conn))
            # conn.start()
            # subscribe_id = '-'.join(map(str, (platform.node(), os.getppid(), os.getpid())))
            conn.connect(login=user,passcode=password)
            subscribe_id = "Queue Test Listener"
            conn.subscribe(destination=dest, id=subscribe_id, ack='client-individual')
            conn.unsubscribe(id=subscribe_id)
            conn.disconnect()
        except Exception as error:
            reason = str(error)
            print("Exception when readig data from queue: " + str(error))
        
        pass

if __name__ == "__main__" :

    try:
        UploadData = Reader()
        UploadData.ConnectToQueue()
        print ("Reader finished.")
    except Exception as Value:
        reason = str(Value)
        pass

这是写入它的代码：

import socket
import threading
import xml.etree.ElementTree as etree
from xml.dom import minidom  # for pretty printing
# import SampleXML
import sys
import os
import math
import time
from time import monotonic
import string
import stomp # for queue support
import platform


class ConnectionListener(stomp.ConnectionListener):
    def __init__(self, connection):
        self.connection = connection
        print "Listener created"

    def on_message(self, message):
        print "Received message with body " + message.body

class UploadData:
    def __init__(self):
        pass
    
    def ConnectToQueue(self):
        #For Production
        user = os.getenv("ACTIVEMQ_USER") or "worthington"
        #user = os.getenv("ACTIVEMQ_USER") or "worthington_test"
        password = os.getenv("ACTIVEMQ_PASSWORD") or "level3"
        host = os.getenv("ACTIVEMQ_HOST") or "localhost"
        port = os.getenv("ACTIVEMQ_PORT") or 61613
        # destination = sys.argv[1:2] or ["/topic/event"]
        # destination = destination[0]
        dest = "from_entec_test"
        #For Production
        # dest = "from_entec"

        try:
            conn = stomp.Connection10(host_and_ports = [(host, port)])
            # conn.start()
            # subscribe_id = '-'.join(map(str, (platform.node(), os.getppid(), os.getpid())))
            subscribe_id = "Queue Test Listener"
            conn.connect(login=user,passcode=password)
            message = "This is a test message."
            conn.send(dest, message, persistent='true')
            print "Sent message containing: " + message
            conn.disconnect()
        except Exception, error:
            reason = str(error)
            print "Exception when writing data to queue: " + str(error)
        
        pass

if __name__ == "__main__" :

    try:
        UploadData = UploadData()
        UploadData.ConnectToQueue()
    except Exception, Value:
        reason = str(Value)
        print "Main routine exception: " + str(Value)
        pass

Answer 1

我对 Python STOMP 客户端不是很熟悉，但是从代码来看，您似乎使用 STOMP 的 'client-individual' 模式进行订阅，这意味着您收到的每条消息都需要您发送一个带有消息 Id 值的 ACK 帧，以便远程可以将其标记为已使用。由于您没有这样做，消息将不会从队列中删除。

作为替代方案，您可以使用 'auto' 确认模式，该模式会在代理发送消息后立即将消息标记为已使用。了解STOMP订阅模式请参考STOMP specification.

如何使用 Python 从 ActiveMQ 队列中删除消息？

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