Django，我无法将函数形式放入 generic.UpdateView

Question

我正在为我所在城市的一所幼儿园制作应用程序。我有儿童模式和支付模式。为了更新孩子，我使用基于 class 的视图通用 UpdateView，为了创建付款，我使用表单和函数视图。当我使用不同的模板时，我的付款表格没有问题，但是当我尝试将它放在同一模板上时，付款表格没有显示并且无法正常工作。是否可以在与 UpdateView class 相同的模板上使用付款表格？我正在使用 UpdateView class 作为个人资料页面，我希望在同一页面上有付款表格。请帮忙。谢谢

型号：

class Kids(models.Model):


    name = models.CharField(max_length=100, blank=True, null=True)
    city_birthday = models.CharField(max_length=100, blank=True, null=True)
    custom_id = models.CharField(max_length=100 ,blank=True, null=True)
    gender = models.CharField(max_length=100, choices=gender_choices, null=True, blank=True)
    address = models.CharField(max_length=250, null=True, blank=True)
    contact_phone = models.CharField(max_length=100, blank=True, null=True)
    family_size = models.IntegerField(null=True, blank=True)
    living_with = models.CharField(max_length=100, choices=living_choices, null=True, blank=True)
    number_of_preschool_kids_in_family = models.IntegerField(null=True, blank=True)
    kid_already_been_in_kindergarten = models.CharField(max_length=100, choices=preschool_choices, 
    null=True, blank=True ,default=False)

    father_name = models.CharField(max_length=100, blank=True, null=True)
    father_education_level = models.CharField(max_length=200, blank=True, null=True)
    father_company = models.CharField(max_length=200, blank=True, null=True)

    mother_name = models.CharField(max_length=100, blank=True, null=True)
    mother_education_level = models.CharField(max_length=200, blank=True, null=True)
    mother_company = models.CharField(max_length=200, blank=True, null=True)

   parent_notes = models.CharField(max_length=500, blank=True, null=True)

   program_choice = models.CharField(max_length=100, choices=kindergarten_program_choice, null=True, 
   blank=True)

    def __str__(self):
        return self.name

    class Meta:
        ordering = ['name']


class Payment(models.Model):
    user = models.ForeignKey(Kids, on_delete=models.CASCADE, blank=True, null=True)
    bank_paper_id = models.IntegerField(null=True, blank=True)
    payment_date = models.CharField(max_length=100, null=True, blank=True)
    paid = models.FloatField(null=True, blank=True)
    need_to_pay = models.FloatField(null=True, blank=True)
    notes = models.CharField(max_length=500, blank=True, null=True)

    def __str__(self):
        return self.user.name

观看次数：

class UpdateKidView(UpdateView):
    model = Kids
    fields = '__all__'
    template_name = 'vrtic/update_kid.html'
    success_url = reverse_lazy('vrtic:kids')


def create_payment(request, pk):
    kid = Kids.objects.get(id=pk)
    payment_form = PaymentForm()

    if request.method == 'POST':
        payment_form = PaymentForm(request.POST)
        if payment_form.is_valid():
            payment = payment_form.save(commit=False)
            payment.user = kid
            payment_form.save()
            return redirect('vrtic:kids')

    context = {
    'payment_form': payment_form,
    'kid': kid
    }
    return render(request, 'vrtic/update_kid.html', context)

形式：

class PaymentForm(forms.ModelForm):

    class Meta:
        model = Payment
        fields = '__all__'

Answer 1

class UpdateKidView(UpdateView):
    model = Kids
    form_class = KidsForm
    second_form_class = PaymentForm
    template_name = 'vrtic/update_kid.html'
    success_url = reverse_lazy('vrtic:kids')

    def get_context_data(self, **kwargs):
        context = super(UpdateKidView, self).get_context_data(**kwargs)
        context['form'] = self.form_class(instance=self.get_object())
        context['second_form'] = self.second_form_class()
        return context

    def post(self, request, **kwargs):
        kids_form = self.form_class(request.POST, request.FILES, instance=self.get_object())
        if kids_form.is_valid():
              kid = kids_form.save()
              payment_form = self.second_form_class(request.POST)
              ...

不是最愉快的解决方案，但你明白了，如果需要更多帮助，请联系我以解释塞尔维亚语，不确定这里的语言规则如何:)

Django，我无法将函数形式放入 generic.UpdateView

Django, i can't put function form inside generic.UpdateView

django

django-models

django-forms

django-class-based-views