如何通过带有 Python 的映射基于任何函数获取 1 和 0 的列表...我收到错误对象不可调用

Question

简而言之，我想做的是基于一个列表 objects = ["bison", "elephant", "horse", "ibis", "sky", "mountain", "building", "flower", "sand", "tree", "field", "road", "tower", "ocean", "cliff", "waterfall"] 如果该字符串列表包含的是另一个列表中元素的子字符串，则获取数字 1 否则为 0 例如，我有另一个列表名称 Lista =['dusthaze-sky', 'rocky-mountain'] 因为它包含天空和山脉应该return[0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

我现在只有下面的代码

Lista = ['dusthaze-sky', 'rocky-mountain']
objects = ["bison", "elephant", "horse", "ibis", "sky", "mountain", "building", "flower", "sand", "tree", "field", "road", "tower", "ocean", "cliff", "waterfall"]
returnList = []
for obj in objects:
  for element in lista: returnList.append(1) if any(map(obj in element, obj)) else returnList.append(0)

这是给我以下错误

Traceback (most recent call last):
  File "main.py", line 22, in <module>
    printBoolArray(readObjects)
  File "main.py", line 10, in printBoolArray
    for m in lista: returnList.append(1) if any(map(n in m, m)) else returnList.append(0)
TypeError: 'bool' object is not callable

希望有什么可以做的，如果可能的话，我希望使用 any 函数

Answer 1

也许这些方面的内容对您有用：

Lista = ['dusthaze-sky', 'rocky-mountain']
objects = ["bison", "elephant", "horse", "ibis", "sky", "mountain", "building", "flower", "sand", "tree", "field", "road", "tower", "ocean", "cliff", "waterfall"]
returnList = []
for obj in objects:
    if any(obj in elem for elem in Lista):
        returnList.append(1)
    else:
        returnList.append(0)

print(returnList)

Out: [0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

请注意，这不是执行此操作的最有效方法，但如果我们尝试对其进行优化，解决方案可能会变得复杂。如果您有任何问题，请随时发表评论。

如果你喜欢列表理解，这里有一行：

returnList = [int(any(obj in elem for elem in Lista)) for obj in objects]

如何通过带有 Python 的映射基于任何函数获取 1 和 0 的列表...我收到错误对象不可调用

How to get a list of 1's and 0's based on any function through a map with Python... I am getting the error object is not callable

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