C++ 套接字、多线程和输出处理

Question

我想聊天 system.It 应该写你：然后你输入的任何内容，只要你从其他用户那里得到文本，只需删除你：输入用户：消息和你：再次。

服务器：

        std::cin.ignore();
        std::thread t1(readData,&acceptedSocket);
        do{
            memset(buffer,0,sizeof(buffer));
            std::cout << "You: ";
            std::cin.getline(buffer,255);
            n = send(acceptedSocket,buffer,strlen(buffer),0);
        }while(n > 0);

客户：

    std::cin.ignore();
    std::thread t1(readData,&connectingSocket);
    do{
        memset(buffer,0,sizeof(buffer));
        std::cout << "You: ";
        std::cin.getline(buffer,255);
        n = send(connectingSocket,buffer,strlen(buffer),0);
    }while(n > 0);

读取数据：

void readData(int *socketPointer){
    int connectingSocket = *socketPointer;
    char buffer[256];
    memset(buffer,0,sizeof(buffer));
    while(recv(connectingSocket,buffer,255,0)){
        std::cout << "\b\b\b\b\bUSER:" << buffer << std::endl << "You: ";
        memset(buffer,0,sizeof(buffer));
    }
}

输出：

服务器：

USER:Hello
USER:How are u doing
Hi
You: You: I am fine
USER:gg
wp
You: You:

客户：

You: Hello
You: How are u doing
USER:Hi
USER:I am fine
gg
You: USER:wp

Wannable 服务器输出：

USER:Hello
USER:How are u doing
You: Hi
You: I am fine
USER:gg
You: wp
You:

Wannable 客户端输出：

You: Hello
You: How are u doing
USER:Hi
USER:I am fine
You: gg
USER:wp
You:

其他thread.Thank你有cin换行，貌似不能换行！

Answer 1

我找到答案了！我注意到当两个线程是运行时——一个从 cin 流获取行，另一个正在输出文本，你需要刷新 cout 缓冲区，所以只有文本出现在 std::endl 之后，这会刷新缓冲并同时放入新行所以：

std::cout.flush():

解决了问题：

    std::cout << "\b\b\b\b\bUSER:" << buffer << std::endl << "You: ";
    std::cout.flush();

C++ 套接字、多线程和输出处理

C++ Sockets,Multithreading and output handling

c++

sockets

multithreading

cout

output