Android/Room/Sqlite : 获取房间中每列的 Maximum/Minimum 值的列表
Android/Room/Sqlite : Get a list of Maximum/Minimum Value of each Column in Room
我的 android 应用程序中有一个 table 看起来与下面给出的相似。
Demo Table
我想查询 table 以获取 table 中每一列的 minimum/maximum 值的列表。
例如,对于给定的样本值:
Sample Values
我希望输出为
最大值:{“值 1”:76.1,“值 2”:1000.0,“值 3”:4897.847,“值 4”:99.0 }
最小值:{“值 1”:2.3,“值 2”:0.0,“值 3”:9.1,“值 4”:99.0 }
使用 Android 中的 Room 实现此目的的最佳方法是什么?
以下是实现您想要的结果的示例。
演示实体(table):-
@Entity
class Demo {
@PrimaryKey
Long id;
Double value1;
Double value2;
Double value3;
Double value4;
Demo(){}
Demo(Double value1, Double value2, Double value3, Double value4) {
this.value1 = value1;
this.value2 = value2;
this.value3 = value3;
this.value4 = value4;
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public Double getValue1() {
return value1;
}
public void setValue1(Double value1) {
this.value1 = value1;
}
public Double getValue2() {
return value2;
}
public void setValue2(Double value2) {
this.value2 = value2;
}
public Double getValue3() {
return value3;
}
public void setValue3(Double value3) {
this.value3 = value3;
}
public Double getValue4() {
return value4;
}
public void setValue4(Double value4) {
this.value4 = value4;
}
}
DemoDao 道:-
@Dao
interface DemoDao {
@Insert
Long insertDemoRow(Demo demo);
@Query("SELECT '{\"Value 1\":'||max(value1)||', \"Value 2\":'||max(value2)||', \"Value 3\":'||max(value3)||' \"Value 4\":'||max(value4) AS Maximum FROM demo")
String getMaxvaluesFromDemo();
@Query("SELECT '{\"Value 1\":'||min(value1)||', \"Value 2\":'||min(value2)||', \"Value 3\":'||min(value3)||' \"Value 4\":'||min(value4) AS Minimum FROM demo")
String getMinvaluesFromDemo();
}
- 单独查询更容易,但可以将它们合并。
DemoDatabase摘要class
@Database(entities = {Demo.class},version = 1)
abstract class DemoDatabase extends RoomDatabase {
abstract DemoDao getDemoDao();
}
最后调用 activity(注意为了方便和简洁,使用了主线程):-
public class MainActivity extends AppCompatActivity {
DemoDatabase db;
DemoDao dao;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
db = Room.databaseBuilder(this,DemoDatabase.class,"demo.db")
.allowMainThreadQueries()
.build();
dao = db.getDemoDao();
dao.insertDemoRow(new Demo(76.1,null,4897.847,null));
dao.insertDemoRow(new Demo(44.2,87.1,47.0,null));
dao.insertDemoRow(new Demo(null,1000.0,12.345,null));
dao.insertDemoRow(new Demo(2.3,0.0,9.1,99.0));
Log.d("DEMOINFO","Maximum " + dao.getMaxvaluesFromDemo());
Log.d("DEMOIBFO","Minimums " + dao.getMinvaluesFromDemo());
}
}
当运行(只设计为运行一次)日志中的结果是:-
D/DEMOINFO: Maximum {"Value 1":76.1, "Value 2":1000.0, "Value 3":4897.847 "Value 4":99.0
D/DEMOIBFO: Minimums{"Value 1":2.3, "Value 2":0.0, "Value 3":9.1 "Value 4":99.0
我的 android 应用程序中有一个 table 看起来与下面给出的相似。
Demo Table
我想查询 table 以获取 table 中每一列的 minimum/maximum 值的列表。
例如,对于给定的样本值:
Sample Values
我希望输出为
最大值:{“值 1”:76.1,“值 2”:1000.0,“值 3”:4897.847,“值 4”:99.0 }
最小值:{“值 1”:2.3,“值 2”:0.0,“值 3”:9.1,“值 4”:99.0 }
使用 Android 中的 Room 实现此目的的最佳方法是什么?
以下是实现您想要的结果的示例。
演示实体(table):-
@Entity
class Demo {
@PrimaryKey
Long id;
Double value1;
Double value2;
Double value3;
Double value4;
Demo(){}
Demo(Double value1, Double value2, Double value3, Double value4) {
this.value1 = value1;
this.value2 = value2;
this.value3 = value3;
this.value4 = value4;
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public Double getValue1() {
return value1;
}
public void setValue1(Double value1) {
this.value1 = value1;
}
public Double getValue2() {
return value2;
}
public void setValue2(Double value2) {
this.value2 = value2;
}
public Double getValue3() {
return value3;
}
public void setValue3(Double value3) {
this.value3 = value3;
}
public Double getValue4() {
return value4;
}
public void setValue4(Double value4) {
this.value4 = value4;
}
}
DemoDao 道:-
@Dao
interface DemoDao {
@Insert
Long insertDemoRow(Demo demo);
@Query("SELECT '{\"Value 1\":'||max(value1)||', \"Value 2\":'||max(value2)||', \"Value 3\":'||max(value3)||' \"Value 4\":'||max(value4) AS Maximum FROM demo")
String getMaxvaluesFromDemo();
@Query("SELECT '{\"Value 1\":'||min(value1)||', \"Value 2\":'||min(value2)||', \"Value 3\":'||min(value3)||' \"Value 4\":'||min(value4) AS Minimum FROM demo")
String getMinvaluesFromDemo();
}
- 单独查询更容易,但可以将它们合并。
DemoDatabase摘要class
@Database(entities = {Demo.class},version = 1)
abstract class DemoDatabase extends RoomDatabase {
abstract DemoDao getDemoDao();
}
最后调用 activity(注意为了方便和简洁,使用了主线程):-
public class MainActivity extends AppCompatActivity {
DemoDatabase db;
DemoDao dao;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
db = Room.databaseBuilder(this,DemoDatabase.class,"demo.db")
.allowMainThreadQueries()
.build();
dao = db.getDemoDao();
dao.insertDemoRow(new Demo(76.1,null,4897.847,null));
dao.insertDemoRow(new Demo(44.2,87.1,47.0,null));
dao.insertDemoRow(new Demo(null,1000.0,12.345,null));
dao.insertDemoRow(new Demo(2.3,0.0,9.1,99.0));
Log.d("DEMOINFO","Maximum " + dao.getMaxvaluesFromDemo());
Log.d("DEMOIBFO","Minimums " + dao.getMinvaluesFromDemo());
}
}
当运行(只设计为运行一次)日志中的结果是:-
D/DEMOINFO: Maximum {"Value 1":76.1, "Value 2":1000.0, "Value 3":4897.847 "Value 4":99.0
D/DEMOIBFO: Minimums{"Value 1":2.3, "Value 2":0.0, "Value 3":9.1 "Value 4":99.0