获取多行问题
Issue getting a number of rows
您好,我要从 psycopg2 转到 asyncpg,我在尝试 return asyncpg 中的多行时遇到问题,在本例中为 10。在 psycopg2 中,我将通过以下方式执行此操作:
psycopg2
cursor.execute(f"SELECT user_id,lvl,xp,total_xp FROM levels WHERE guild_id = {str(701547632666525246)} ORDER BY GREATEST(total_xp) DESC")
res = cursor.fetchmany(10)
asycpg
res = await conn.fetch("SELECT user_id,lvl,xp,total_xp FROM levels WHERE guild_id = ORDER BY GREATEST(total_xp) DESC", ctx.guild.id)
我有点卡在 asyncpg 部分,我们将不胜感激。
这是我正在处理的内容:
@commands.command()
async def ranking(self, ctx):
"""Displays top 10 Active Members in the server"""
if ctx.message.channel.name == "commands":
async with self.bot.pool.acquire() as conn:
res = await conn.fetch("SELECT user_id,lvl,xp,total_xp FROM levels WHERE guild_id = ORDER BY GREATEST(total_xp) DESC", ctx.guild.id)
#0: user_id, 1: lvl
mess = "Top 10 active members"
x = 1
for ele in res:
user = self.bot.get_user(int(ele[0]))
mess += "**{}.** {} on **Level {: <3}** with **{: <4} XP**\n\n".format(x,user.name,ele[1], ele[2])
x+=1
embed = discord.Embed(title="Leaderboard", description=f"{mess}")
await ctx.send(embed=embed)
else:
await ctx.send("Can't use this command in this channel.")
您可以简单地使用 LIMIT
子句
query = """
SELECT user_id,lvl, xp, total_xp
FROM levels
WHERE guild_id =
ORDER BY GREATEST(total_xp) DESC
LIMIT 10
"""
await conn.fetch(query, ctx.guild.id)
它适用于 psycopg2
和 asyncpg
您好,我要从 psycopg2 转到 asyncpg,我在尝试 return asyncpg 中的多行时遇到问题,在本例中为 10。在 psycopg2 中,我将通过以下方式执行此操作:
psycopg2
cursor.execute(f"SELECT user_id,lvl,xp,total_xp FROM levels WHERE guild_id = {str(701547632666525246)} ORDER BY GREATEST(total_xp) DESC")
res = cursor.fetchmany(10)
asycpg
res = await conn.fetch("SELECT user_id,lvl,xp,total_xp FROM levels WHERE guild_id = ORDER BY GREATEST(total_xp) DESC", ctx.guild.id)
我有点卡在 asyncpg 部分,我们将不胜感激。
这是我正在处理的内容:
@commands.command()
async def ranking(self, ctx):
"""Displays top 10 Active Members in the server"""
if ctx.message.channel.name == "commands":
async with self.bot.pool.acquire() as conn:
res = await conn.fetch("SELECT user_id,lvl,xp,total_xp FROM levels WHERE guild_id = ORDER BY GREATEST(total_xp) DESC", ctx.guild.id)
#0: user_id, 1: lvl
mess = "Top 10 active members"
x = 1
for ele in res:
user = self.bot.get_user(int(ele[0]))
mess += "**{}.** {} on **Level {: <3}** with **{: <4} XP**\n\n".format(x,user.name,ele[1], ele[2])
x+=1
embed = discord.Embed(title="Leaderboard", description=f"{mess}")
await ctx.send(embed=embed)
else:
await ctx.send("Can't use this command in this channel.")
您可以简单地使用 LIMIT
子句
query = """
SELECT user_id,lvl, xp, total_xp
FROM levels
WHERE guild_id =
ORDER BY GREATEST(total_xp) DESC
LIMIT 10
"""
await conn.fetch(query, ctx.guild.id)
它适用于 psycopg2
和 asyncpg