运行 turtle 文件的 SPARQL 查询

Question

我正在尝试运行使用 python 对 turtle 文件进行 SPARQL 查询，但是我的 sparql returns 所有条目，我如何 return 条目名称="Idham Al-Taif Mahmoud"?

乌龟档案：

<http://example.org/person/a6376-dh3642> <http://dbpedia.org/ontology/hasName> "Idham Al-Taif Mahmoud".
<http://example.org/person/a6376-dh3642> <http://dbpedia.org/ontology/diedOn> "28 Feb 2017".
<http://example.org/person/a6376-dh3642> <http://dbpedia.org/ontology/hasAge> "adult".
<http://example.org/person/a6376-dh3642> <http://dbpedia.org/ontology/hasSex> "male".
<http://example.org/person/a6376-dh3642> <http://dbpedia.org/ontology/diedIn> "Samarra, south of Salah Al-Din".
<http://example.org/person/a6363-fn3690> <http://dbpedia.org/ontology/hasName> "Shukran Ghanim Hussein".
<http://example.org/person/a6363-fn3690> <http://dbpedia.org/ontology/diedOn> "26 Feb 2017".
<http://example.org/person/a6363-fn3690> <http://dbpedia.org/ontology/hasAge> "child".
<http://example.org/person/a6363-fn3690> <http://dbpedia.org/ontology/hasSex> "male".
<http://example.org/person/a6363-fn3690> <http://dbpedia.org/ontology/diedIn> "Hay Koor, west Mosul".
<http://example.org/person/a6348-sz3469> <http://dbpedia.org/ontology/hasName> "Munther Al-Ajaj ".
<http://example.org/person/a6348-sz3469> <http://dbpedia.org/ontology/hasMaritalStatus> "married".
<http://example.org/person/a6348-sz3469> <http://dbpedia.org/ontology/hasParentalStatus> "parent".
<http://example.org/person/a6348-sz3469> <http://dbpedia.org/ontology/diedOn> "25 Feb 2017".
<http://example.org/person/a6348-sz3469> <http://dbpedia.org/ontology/hasAge> "adult".
<http://example.org/person/a6348-sz3469> <http://dbpedia.org/ontology/hasSex> "male".
<http://example.org/person/a6348-sz3469> <http://dbpedia.org/ontology/diedIn> "Al-Mazra'a village, Baiji, north of Salah Al-Din".
<http://example.org/person/a6381-xz3480> <http://dbpedia.org/ontology/hasName> "Shifa Gerdi/Born Shifa Zikri Ibrahim Gerdi".
<http://example.org/person/a6381-xz3480> <http://dbpedia.org/ontology/diedOn> "25 Feb 2017".
<http://example.org/person/a6381-xz3480> <http://dbpedia.org/ontology/hasAge> "young adult".
<http://example.org/person/a6381-xz3480> <http://dbpedia.org/ontology/hasSex> "female".
<http://example.org/person/a6381-xz3480> <http://dbpedia.org/ontology/diedIn> "west Mosul".

python代码：

import rdflib

filename = "turtle.ttl"


g = rdflib.Graph()

result = g.parse(filename, format='ttl')
print(result)

query = """

SELECT ?person
WHERE {
    ?person <http://dbpedia.org/ontology/hasName> "Idham Al-Taif Mahmoud"
}

"""

g.query(query)
for stmt in g:
    print(stmt)

Answer 1

我认为您的问题出在方法上。 Here 是一个 link，其中包含一个很好的示例，说明您想要做什么。

以下脚本适合我：

import rdflib
  
filename = "turtle.ttl"


g = rdflib.Graph()

g.parse(filename, format='ttl')

query = """

SELECT ?person
WHERE {
    ?person <http://dbpedia.org/ontology/hasName> "Idham Al-Taif Mahmoud"
}

"""

qres = g.query(query)

for row in qres :
        print("%s" % row)

请注意，我将查询结果分配给一个新变量 qres，而且 parse 方法是无效的，即它不会 return 一个像你这样的值有。

最后的%标志只是为了打印一个人类可读的结果，但你完全可以去掉它们。

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