将双精度值 (1.005) 舍入为 (1.01)

Rounding a double value (1.005) to (1.01)

swift

中数字 1.005 的四舍五入问题

将 1.005 四舍五入到小数点后两位的结果是 1.0 而不是 1.01 如何解决?

for i in 1..<11 {
    let value = Double(i) + 0.005
    let roundedValue = round(value * 100) / 100.0
    print(value, roundedValue)
}

输出:

1.005  -> 1.0
2.005  -> 2.01
3.005  -> 3.01
4.005  -> 4.01
5.005  -> 5.01
6.005  -> 6.01
7.005  -> 7.01
8.005  -> 8.01
9.005  -> 9.01
10.005  -> 10.01

只需使用 NumberFormatter 并将 roundingMode 设置为 halfUp:

extension Formatter {
    static let number: NumberFormatter = {
        let formatter = NumberFormatter()
        formatter.numberStyle = .decimal
        formatter.minimumFractionDigits = 2
        formatter.maximumFractionDigits = 2
        formatter.roundingMode = .halfUp
        return formatter
    }()
}

Formatter.number.string(for: 1.005)   // "1.01"
Formatter.number.string(for: 2.005)   // "1.01"
Formatter.number.string(for: 3.005)   // "1.01"
Formatter.number.string(for: 4.005)   // "1.01"
Formatter.number.string(for: 5.005)   // "1.01"
Formatter.number.string(for: 6.005)   // "1.01"
Formatter.number.string(for: 7.005)   // "1.01"
Formatter.number.string(for: 8.005)   // "1.01"
Formatter.number.string(for: 9.005)   // "1.01"
Formatter.number.string(for: 10.005)  // "1.01"