我需要在同一个 tkinter 组合框上执行多个绑定语句，但只有第一个可以工作

Question

我试图将多个绑定语句添加到一个组合框中，但它不起作用。

我有一个 tkinter window 可以将数据输入到 sql 数据库中，该数据库具有多个相关的组合框，以便在输入错误的内容会导致致命错误的地方更容易输入数据。州名组合框会将州缩写排列在一个组合框中，另一个组合框用于该州可用的国家公园名称。选择的公园随后会触发另一个组合框，其中唯一的选项应该是公园的缩写。我遇到的问题是将州缩写和公园名称组合框绑定到州组合框。它们在两个单独的语句中，我一次只能得到一个来工作。我必须注释掉状态缩写绑定才能使用公园名称和公园缩写组合框，反之亦然。有什么想法吗？

from tkinter import *
from tkinter import ttk
# list of states
states = ['Alaska', 'Arizona', 'Arkansas']
# dictionaries
STATE_DICT = {
        'state_name': {
            'AK': 'Alaska',
            'AR': 'Arkansas',
            'AZ': 'Arizona'}
    }
PARKS_DICT = {
    'state_name': {
        'DENA': 'Alaska',
        'GLBA': 'Alaska',
        'KATM': 'Alaska',
        'KEFJ': 'Alaska',
        'HOSP': 'Arkansas',
        'GRCA': 'Arizona',
        'PEFO': 'Arizona',
        'SAGU': 'Arizona'
        },
    'park_name': {
        'DENA': 'Denali National Park',
        'GLBA': 'Glacier Bay National Park',
        'KATM': 'Katmai National Park',
        'KEFJ': 'Kenai Fjords National Park',
        'HOSP': 'Hot Springs National Park',
        'GRCA': 'Grand Canyon National Park',
        'PEFO': 'Petrified Forest National Park',
        'SAGU': 'Saguaro National Park'}
}
root2 = Tk()
root2.title("data_entry_form")
root2.geometry("800x500")

state_name_label = Label(root2, text="State Name", width=20, font=("bold", 12),bd=1, relief="raised")
state_abbr_label =  Label(root2, text="State Abbr", width=20, font=("bold", 12),bd=1, relief="raised")
park_name_label =  Label(root2, text="Park Name", width=20, font=("bold", 12),bd=1, relief="raised")
park_abbr_label =  Label(root2, text="Park Abbr", width=20, font=("bold", 12),bd=1, relief="raised")
nearest_city_label =  Label(root2, text="Nearest City", width=20, font=("bold", 12),bd=1, relief="raised")
geo_location_label =  Label(root2, text="Geo Location", width=20, font=("bold", 12),bd=1, relief="raised")
hike_name_label = Label(root2, text="Hike Name", width=20, font=("bold", 12),bd=1, relief="raised")
length_miles_label =  Label(root2, text="Length in Miles", width=20, font=("bold", 12),bd=1, relief="raised")
elevation_gain_feet_label =  Label(root2, text="Elevation in Feet", width=20, font=("bold", 12),bd=1, relief="raised")
nps_difficulty_rating_label =  Label(root2, text="NPS Difficulty Rating", width=20, font=("bold", 12),bd=1, relief="raised")
route_type_label =  Label(root2, text="Route Type", width=20, font=("bold", 12),bd=1, relief="raised")
# Data entry fields
hike_name_entry = Entry(root2,width=100)
nearest_city_entry = Entry(root2,width=50)
geo_location_entry = Entry(root2,width=50)
length_miles_entry = Entry(root2,width=50)
elevation_gain_feet_entry = Entry(root2,width=50)
# submit button
submitbutton = Button(root2, text='Submit New Hike!', width=20, bg="black", fg='white')
# comboboxes
def parks_list(e):
    p=list()
    x=list()
    for key,value in PARKS_DICT['state_name'].items():
        if value==state_combo.get():
            p.append(key)
    for k,v in PARKS_DICT['park_name'].items():
        if k in p:
            x.append(v)
            park_combo.config(value=x)
def park_abb(e):
    p=list()
    for key,value in PARKS_DICT['park_name'].items():
        if value==park_combo.get():
            p.append(key)
            park_abbr_combo.config(value=p)
def state_abb(e):
    p=list()
    for key,value in STATE_DICT['state_name'].items():
        if value==state_combo.get():
            p.append(key)
            state_abbr_combo.config(value=p)
state_combo = ttk.Combobox(root2, value=states)
state_combo.current(0)

#state_combo.bind("<<ComboboxSelected>>", state_abb) #-have to # this out to get the other statement to work.
state_combo.bind("<<ComboboxSelected>>", parks_list)

state_abbr_combo = ttk.Combobox(root2, value=[" "])
state_abbr_combo.current(0)

park_combo = ttk.Combobox(root2, value=[" "])
park_combo.current(0)
park_combo.bind("<<ComboboxSelected>>", park_abb)

park_abbr_combo = ttk.Combobox(root2, value=[" "])
park_abbr_combo.current(0)

nps_difficulty_rating= ttk.Combobox(root2, value =range(1,6))
route_type_combo=ttk.Combobox(root2, value=['loop','out and back','point to point'])
# Grid placement
state_name_label.grid(row=1, column=0, padx=10, pady=10)
state_combo.grid(row=1, column=1, padx=10, pady=10)
state_abbr_label.grid(row=2, column=0, padx=10, pady=10)
state_abbr_combo.grid(row=2, column=1, padx=10, pady=10)
park_name_label.grid(row=3, column=0, padx=10, pady=10)
park_combo.grid(row=3, column=1, padx=10, pady=10)
park_abbr_label.grid(row=4, column=0, padx=10, pady=10)
park_abbr_combo.grid(row=4, column=1, padx=10, pady=10)
nearest_city_label.grid(row=5, column=0, padx=10, pady=10)
nearest_city_entry.grid(row=5, column=1, padx=10, pady=10)
geo_location_label.grid(row=6, column=0, padx=10, pady=10)
geo_location_entry.grid(row=6, column=1, padx=10, pady=10)
hike_name_label.grid(row=7, column=0, padx=10, pady=10)
hike_name_entry.grid(row=7, column=1, padx=10, pady=10)
length_miles_label.grid(row=8, column=0, padx=10, pady=10)
length_miles_entry.grid(row=8, column=1, padx=10, pady=10)
elevation_gain_feet_label.grid(row=9, column=0, padx=10, pady=10)
elevation_gain_feet_entry.grid(row=9, column=1, padx=10, pady=10)
nps_difficulty_rating_label.grid(row=10, column=0, padx=10, pady=10)
nps_difficulty_rating.grid(row=10, column=1, padx=10, pady=10)
route_type_label.grid(row=11, column=0, padx=10, pady=10)
route_type_combo.grid(row=11, column=1, padx=10, pady=10)
submitbutton.grid(row=12, column=1, padx=10, pady=10)
root2.mainloop()

Answer 1

虽然可以进行多个绑定，但我认为这样做没有任何好处。相反，创建一个调用其他函数的函数。

def state_combo_changed(event):
    state_abb(event)
    parks_list(abb)

state_combo.bind("<<ComboboxSelected>>", state_combo_changed)

如果您坚持要进行两个单独的绑定，您可以将 add 属性设置为 True:

state_combo.bind("<<ComboboxSelected>>", state_abb)
state_combo.bind("<<ComboboxSelected>>", parks_list, add=True)

我需要在同一个 tkinter 组合框上执行多个绑定语句，但只有第一个可以工作

I need to do multiple bind statements on the same tkinter combobox, but only the first one will work

python

binding

combobox

tkinter