将列表中的每个元素替换为字典列表中的另一个元素

Question

简而言之，我需要做的是为列表中的每个元素从字典列表中获取相应的值并替换它例如...对于以下输入列表

list1 = ['gui', 'guigui', 'guiguigguuii']
list2 = ['gui', 'gui', 'gui', 'gui', 'gui', 'gui']

我应该在那些词典列表中查找

dictlist1 = [{'gui': 'ya'}, {'guigui': 'lyub'}, {'guiguigguuii': 'htr'}]
dictlist2 = [{'gui': 'asdf'}]

它应该输出

output1 = ['ya', 'lyub', 'htr']
output2 = ['asdf', 'asdf', 'asdf', 'asdf', 'asdf', 'asdf']

我写了一个代码...但是它不适用于第二个数据样本

print(' '.join([item for sublist in [[value for key, value in d.items()] for d in lista] for item in sublist]))

Answer 1

在这里，抱歉，如果它有点长，但我认为使用这个模板你可以找到一些东西。

list1 = ['gui', 'guigui', 'guiguigguuii']
replace = [{'gui': 'ya'}, {'guigui': 'lyub'}, {'guiguigguuii': 'htr'}]
newList = []
#iterate through list1
for words in list1:
    count = 0
    #iterate through replaces dicts
    for dicts in replace:
        #Check if any word in list1 can be replaced
        if words == list(dicts.keys())[0]:newList.append(dicts[list(dicts.keys())[0]])
        count += 1
print(newList)

输出

['ya', 'lyub', 'htr']

将列表中的每个元素替换为字典列表中的另一个元素

Replace each element from a list with another from a dictionary list

python

dictionary

for-loop

list-comprehension

list