Python-我需要我的程序来计算掷出 2 个骰子的每个结果发生了多少次。（2-12是可能的结果）

Question

import random

num_rolls = int(input('Enter number of rolls:\n'))
results = int()

if num_rolls >= 1:
    for i in range(num_rolls):
        die1 = random.randint(1,6)
        die2 = random.randint(1,6)
        roll_total = die1 + die2
        results =+ 1
    print('Roll %d is %d (%d + %d)' % (i, roll_total, die1, die2))       
    for j in range(results):
        print('\nDice roll statistics:')
        print('%ds:'% roll_total, results)

输出应该是这样的：

卷 1 是 6 (3 + 3)

第 2 卷是 7 (3 + 4)

第 3 卷是 6 (4 + 2)

第 4 卷是 5 (2 + 3)

掷骰统计数据：

6s: 1

7s: 2

6s: 3

5s: 4

Answer 1

因为 roll_total = die1 + die2 每次迭代都会覆盖 roll_total。

您想roll_total += (die1 + die2).

(PS: 调试提示，如果你在你的 for 循环中使用 print(roll_total) 你可能会发现这个)

Answer 2

假设您尝试为每个卷打印 roll_total，将每个 roll_total 的值存储为 results 中的列表。

import random

num_rolls = int(input('Enter number of rolls:\n'))
results = []

if num_rolls >= 1:
    for i in range(num_rolls):
        die1 = random.randint(1,6)
        die2 = random.randint(1,6)
        roll_total = die1 + die2
        results.append(roll_total)
    print('Roll %d is %d (%d + %d)' % (i, roll_total, die1, die2))       
    print('\nDice roll statistics:')
    for j in range(len(results)):
        print(f'{j+1}: {results[j]}')

示例输出：

Enter number of rolls:
6
Roll 5 is 9 (3 + 6)

Dice roll statistics:
1: 7
2: 7
3: 7
4: 9
5: 6
6: 9

Answer 3

假设你想要下一个输出：

Enter number of rolls:
11
Roll 1 is 6 (2 + 4)
Roll 2 is 7 (2 + 5)
Roll 3 is 6 (4 + 2)
Roll 4 is 3 (1 + 2)
Roll 5 is 6 (3 + 3)
Roll 6 is 2 (1 + 1)
Roll 7 is 9 (6 + 3)
Roll 8 is 5 (3 + 2)
Roll 9 is 6 (5 + 1)
Roll 10 is 5 (3 + 2)
Roll 11 is 7 (4 + 3)

Dice roll statistics:
6s: 4
7s: 2
3s: 1
2s: 1
9s: 1
5s: 2

你可以做到

import random

num_rolls = int(input('Enter number of rolls:\n'))
statistics = []
helper = 0

if num_rolls >= 1:
    for i in range(1,num_rolls+1):
        die1 = random.randint(1,6)
        die2 = random.randint(1,6)
        roll_total = die1 + die2
        print('Roll %d is %d (%d + %d)' % (i, roll_total, die1, die2))
        stat = '%ds:'% roll_total
        final = [stat,1]
        if len(statistics) > 0:
            for i in statistics:
                if stat in i:
                    i[1] += 1
                    helper = 1
                    break
            if helper == 0:
                statistics.append(final)
            helper = 0
        else:
            statistics.append(final)
 
print('\nDice roll statistics:')
for i in statistics:
    print(*i)

Python-我需要我的程序来计算掷出 2 个骰子的每个结果发生了多少次。（2-12是可能的结果）

Python-I need my program to count how many times each outcome of 2 dice being rolled has happened. (2-12 are the possible outcomes)

python

dice

Python-我需要我的程序来计算掷出 2 个骰子的每个结果发生了多少次。 （2-12是可能的结果）

Python-I need my program to count how many times each outcome of 2 dice being rolled has happened. (2-12 are the possible outcomes)

python

dice

Python-我需要我的程序来计算掷出 2 个骰子的每个结果发生了多少次。（2-12是可能的结果）