如何在 "def request()" return 中直接响应
How to in "def request()" return the response directly
如标题,我想在“def request()”中处理数据,并return直接响应;
我不想流经目标服务器;
这种方式可行吗?谢谢!!!
这是一个关于如何做到这一点的例子:
"""Send a reply from the proxy without sending any data to the remote server."""
from mitmproxy import http
def request(flow: http.HTTPFlow) -> None:
if flow.request.pretty_url == "http://example.com/path":
flow.response = http.Response.make(
200, # (optional) status code
b"Hello World", # (optional) content
{"Content-Type": "text/html"} # (optional) headers
)
来源:https://github.com/mitmproxy/mitmproxy/blob/main/examples/addons/http-reply-from-proxy.py
如标题,我想在“def request()”中处理数据,并return直接响应;
我不想流经目标服务器;
这种方式可行吗?谢谢!!!
这是一个关于如何做到这一点的例子:
"""Send a reply from the proxy without sending any data to the remote server."""
from mitmproxy import http
def request(flow: http.HTTPFlow) -> None:
if flow.request.pretty_url == "http://example.com/path":
flow.response = http.Response.make(
200, # (optional) status code
b"Hello World", # (optional) content
{"Content-Type": "text/html"} # (optional) headers
)
来源:https://github.com/mitmproxy/mitmproxy/blob/main/examples/addons/http-reply-from-proxy.py