运算符 "NOT LIKE" with peewee

Question

我需要一个查询，其中内容“不喜欢”是

的一个值

query = (Table
                .select()
                .where((Table.lastseen < olddate.isoformat()) &
                       (Table.used==1) &
                       (Table.ip !% '%/%' ))
                .order_by(Table.lastseen.asc())
            )

！行不通，如何取消 LIKE？

Answer 1

您必须使用 ~ 而不是 !。这就是否定在 peewee 中的工作原理。您需要使用括号将您希望否定的查询包装起来。在你的情况下 (~(Table.ip % '%/%' )).

query = (Table
                .select()
                .where((Table.lastseen < olddate.isoformat()) &
                       (Table.used==1) &
                       (~(Table.ip % '%/%' )))
                .order_by(Table.lastseen.asc())
            )

最小可重现示例（摘自 peewee 文档的片段）

from datetime import date
from peewee import *

db = SqliteDatabase('people.db')

class Person(Model):
    name = CharField()
    birthday = DateField()

    class Meta:
        database = db # This model uses the "people.db" database.

db.connect()
db.create_tables([Person])

uncle_bob = Person(name='Bob', birthday=date(1960, 1, 15))
uncle_bob.save()
aunt_alice = Person(name='Alice', birthday=date(1965, 1, 15))
aunt_alice.save()

query = Person.select().where(~(Person.name % 'B*')) # not like 'B%', wildcard changes according to database, `*` instead of `%` for SQLite

for i in query:
    print(i.name) # Alice

运算符 "NOT LIKE" with peewee

Operator "NOT LIKE" with peewee

python

mysql

peewee