在 python 中返回主菜单

Question

只是一个快速的（我对 Python 中的编码非常陌生，但如果有帮助的话，我有一年左右的 R 经验）。

我在下面打印了我的编码，其中有一个菜单，用户可以在其中 select 一个选项，将他们引导到某个 activity（A、B、C、D , X)，它比我发布的内容更丰富，但我不想提交更大的文本代码墙。

def printMenu ():
    print("Playing Statistics Calculator")
    print("A: Positions in Basketball and relevent Key Performance Indicators")
    print("B: Calculate your per-game statistics")
    print("C: Compare your statistics to other players in your position")
    print("X: Exit")

def main():
    choice = printMenu()
    choice

main()

selection = input("Please choose a selection: ")

if selection == "A":
    print("You are interested in looking at the Key Performance Indicators (KPIs) that we think are important for each position. Please select a position below:")
    main()
    selection
elif selection == "B":
    print("Now you know the important KPIs related to each position, which position are you interested in, in our team?")
    main()
    selection
elif selection == "D":
    print("comparison calculations in here")
    main()
    selection
elif selection == "X":
    exit()
else:
    print("Try again, please ensure the letters are in capitals and are shown in menu")
    main()
    selection

我的问题是，当我尝试在 activity 结束时将用户带回主菜单时，它会按预期打印菜单，但不允许用户输入 selection，如果它确实允许，它只是停止程序，而不是循环返回并运行再次正确。

任何建议都很好，在此先感谢！

Answer 1

试试下面的结构

def printMenu():
    print("Playing Statistics Calculator")
    print("A: Positions in Basketball and relevent Key Performance Indicators")
    print("B: Calculate your per-game statistics")
    print("C: Compare your statistics to other players in your position")
    print("X: Exit")
    return input("Please choose a selection: ").upper()

def program(selection):
    if selection == "A":
        print("You are interested in looking at the Key Performance Indicators (KPIs) that we think are important for each position. Please select a position below:")
    elif selection == "B":
        print("Now you know the important KPIs related to each position, which position are you interested in, in our team?")
    elif selection == "C":
        print("comparison calculations in here")
    else:
        print("Try again, please ensure the letter is shown in the menu.")

selection = printMenu()
while selection != 'X':
    program(selection)
    print()
    selection = printMenu()

Answer 2

问题是，当您在 else/if 语句中调用“选择”时，它不会返回处理输入，所以我认为最好的选择是将该部分定义为函数也一样，需要的时候调用

def printMenu ():
    print("Playing Statistics Calculator")
    print("A: Positions in Basketball and relevent Key Performance Indicators")
    print("B: Calculate your per-game statistics")
    print("C: Compare your statistics to other players in your position")
    print("X: Exit")

def main():
    choice = printMenu()
    choice

main()

def processInput()
    selection = input("Please choose a selection: ")
    if selection == "A":
        print("You are interested in looking at the Key Performance Indicators (KPIs) that we think are important for each position. Please select a position below:")
        main()
        processInput()
    elif selection == "B":
        print("Now you know the important KPIs related to each position, which position are you interested in, in our team?")
        main()
        processInput()
    elif selection == "D":
        print("comparison calculations in here")
        main()
        processInput()
    elif selection == "X":
        exit()
    else:
        print("Try again, please ensure the letters are in capitals and are shown in menu")
        main()
        processInput()

processInput()

我会做这样的事情，尽管你应该做最适合你的程序的事情

在 python 中返回主菜单

Returning back to main menu in python

python

menu