pandas：仅当另一列中的值匹配时才计算行之间的重叠词（多个实例的问题）

Question

我有一个如下所示的数据框，但有很多行：

import pandas as pd

data = {'intent':  ['order_food', 'order_food','order_taxi','order_call','order_call','order_call','order_taxi'],
'Sent': ['i need hamburger','she wants sushi','i need a cab','call me at 6','she called me','order call','i would like a new taxi' ],
'key_words': [['need','hamburger'], ['want','sushi'],['need','cab'],['call','6'],['call'],['order','call'],['new','taxi']]}

df = pd.DataFrame (data, columns = ['intent','Sent','key_words'])

我使用下面的代码（不是我的解决方案）计算了 jaccard 相似度：

def lexical_overlap(doc1, doc2): 
    words_doc1 = set(doc1) 
    words_doc2 = set(doc2)

    intersection = words_doc1.intersection(words_doc2)    
    return intersection

并修改了给出的代码以比较每两行之间的重叠词并从中创建一个数据框：

overlapping_word_list=[]

for val in list(combinations(range(len(data_new)), 2)):
     overlapping_word_list.append(f"the shared keywords between {data_new.iloc[val[0],0]} and {data_new.iloc[val[1],0]} sentences are: {lexical_overlap(data_new.iloc[val[0],1],data_new.iloc[val[1],1])}")
#creating an overlap dataframe
banking_overlapping_words_per_sent = DataFrame(overlapping_word_list,columns=['overlapping_list'])

的回答对我有帮助，我对其进行了一些更改以获得我喜欢的输出：

for intent in df.intent.unique():
    # loc returns a DataFrame but we need just the column
    rows = df.loc[df.intent == intent,['intent','key_words','Sent']].values.tolist()
    combos = combinations(rows, 2)
    for combo in combos:
        x, y = rows
        overlap = lexical_overlap(x[1], y[1])
        print(f"Overlap of intent ({x[0]}) for ({x[2]}) and ({y[2]}) is {overlap}")

问题是，当有更多相同意图的实例时，我运行进入错误： ValueError：要解压的值太多（预期为 2）

我不知道如何处理我数据集中的更多示例

Answer 1

你想要这个吗？

from itertools import combinations
from operator import itemgetter
items_to_consider = []
for item in list(combinations(zip(df.Sent.values, map(set,df.key_words.values)),2)):
    keywords = (list(map(itemgetter(1),item)))
    intersect = keywords[0].intersection(keywords[1])
    if len(intersect) > 0:
        str_list = list(map(itemgetter(0),item))
        str_list.append(intersect)
        items_to_consider.append(str_list)


for i in items_to_consider:
    for item in i[2]:
        if item in i[0] and item in i[1]:
            print(f"Overlap of intent (order_food) for ({i[0]}) and ({i[1]}) is {item}")

pandas：仅当另一列中的值匹配时才计算行之间的重叠词（多个实例的问题）

pandas: calculate overlapping words between rows only if values in another column match (issue with multiple instances)

python

combinations

list

pandas

sentence-similarity