如何在不单击项目的情况下显示菜单项的内容

Question

我想显示第一个菜单项的内容，而不是点击它，使其成为打开应用程序时显示的默认内容。我已经尝试了我能想到的一切。 Console.log 显示“selectedView”可观察值类似于“View {title: “Event List”, templateName: “EventList”}”，所以我尝试将其设置为该值，但它仍然有效.

<div class="inServMenu" data-bind="foreach: views">
    <a href="#" class="inServMenuItem" data-bind="text: title, click: $root.selectedView"></a>
</div>

<div data-bind="with: selectedView">
    <div data-bind="template: { name: templateName }"></div>
</div>

<script id="EventList" type="text/html">
 <span>"Here's the Event List..."</span>
</script>

<script id="RosterList" type="text/html">
 <span>"Here's the Roster List..."</span>
</script> var View = function (title, templateName) {
    this.title = title;
    this.templateName = templateName;
};

// VIEWMODEL
var viewModel = {
    selectedView: ko.observable(),
    views: ko.observableArray([
        new View('Event List', 'EventList'),
        new View('Roster List', 'RosterList')
    ]),
}

ko.applyBindings(viewModel);```

[Here's a jsfiddle][1]


  [1]: http://jsfiddle.net/jjfrick/hmfubkcr/18/

Answer 1

您需要稍微更改视图模型构造函数，以便可以引用它：

function ViewModel () {
    var vm = this;
    vm.views = ko.observableArray([
        new View('Event List', 'EventList'),
        new View('Roster List', 'RosterList')
    ]);
    vm.selectedView = ko.observable(vm.views()[0])
}

ko.applyBindings(new ViewModel());

如何在不单击项目的情况下显示菜单项的内容

How can I display a menu item's contents without clicking on the item

templates

knockout.js

menu