查询以获取映射到同一代码的两个不同项目的总和

Question

我有房间的库存 table :

dtm	hotelid	roomcode	intqty
2000-01-04	23	svr	9
2000-01-04	23	ovb	9

这是我的映射 table :

hotelid	roomcode1	roomcode2	externalroom
23	svr	ovb	023

我正在尝试获取上述两个房间在同一日期的库存 table 的 intqty 总和：这是我目前所拥有的：

select
    a.dtm as InvDate,
    a.intResortID as ResortId,
    a.strRoomType as RoomType,
    sUM(a.intQty) as InvCount,
    am.externalRoomId
from
    dbo.tblAvailable c
    join dbo.tblAvailable a on a.dtm = c.dtm
       and a.intResortID = c.intResortID
       and a.strRoomType = c.strRoomType
    join dbo.tblResorts r on r.intResortID = a.intResortID
    join bbtest.externalResortMap arm on arm.ResortID = a.intResortID
    join bbtest.externalRoomMap am on am.RoomId = a.strRoomType
group by
    a.dtm,
    a.intResortID,
    a.strRoomType,
    a.intQty,
    am.externalRoomId
order by
    invDate;

预期结果是：

Invdate	ResortId	RoomType	InvCount	externalRoomId
2000-01-04	23	svr	18	023

查询输出：

Invdate	ResortId	RoomType	InvCount	externalRoomId
2000-01-04	23	svr	9	023
2000-01-04	23	ovb	9	023

Answer 1

不确定您为什么两次加入 tblAvailable，但如果我没有犯任何错误，这就是您需要做的事情：

select
    a.dtm as InvDate,
    a.intResortID as ResortId,
    am.RoomId_1 as RoomType,
    sum(a.intQty) as InvCount,
    am.externalRoomId
from
    dbo.tblAvailable a 
    join dbo.tblResorts r on r.intResortID = a.intResortID
    join bbtest.externalResortMap arm on arm.ResortID = a.intResortID
    join bbtest.externalRoomMap am 
       on a.strRoomType in (am.RoomId_1 ,am.RoomId_2)
group by
    a.dtm,
    a.intResortID,
    am.RoomId_1,   
    am.externalRoomId
order by
    invDate;

查询以获取映射到同一代码的两个不同项目的总和

query to Get sum of two different items that is mapped onto same code

sql

mapping

stored-procedures

sql-server-2008