在结果中添加一列，显示按年份分组的序号

Question

这些 SQL 能够添加具有递增数字（1、2、3、4 等）的列

select year, quarter, uploaddate, wagecount, SUM(1) 
OVER (ORDER BY year, quarter, uploaddate) as SequentialNumbers from SAMPLE_DATA
order by year, quarter, uploaddate

或

select your_query.*, rownum
  from (select year, quarter, uploaddate, wagecount 
          from SAMPLE_DATA) your_query

结果看起来像这样

Year	Quarter	UploadDate	WageCount	SequentialNumbers
2021	1	01-JAN-21	2	1
2021	1	02-JAN-21	2	2
2021	1	03-JAN-21	1	3
2021	1	04-JAN-21	5	4

是否可以采取下一个大胆的步骤，使每年都有自己的序号。换句话说，结果最终会像这样

像这样

Year	Quarter	UploadDate	WageCount	SequentialNumbers
2019	1	01-JAN-21	2	1
2019	1	02-JAN-21	2	2
2019	1	03-JAN-21	1	3
2019	1	04-JAN-21	5	4
2020	1	01-JAN-20	2	1
2020	1	02-JAN-20	2	2
2020	1	03-JAN-20	1	3
2020	1	04-JAN-20	5	4
2021	1	01-JAN-21	2	1
2021	1	02-JAN-21	2	2
2021	1	03-JAN-21	1	3
2021	1	04-JAN-21	5	4

示例数据如下：

CREATE TABLE SAMPLE_DATA (
    YEAR VARCHAR2(4) NULL,
    QUARTER NUMBER(1,0) NULL,
    UPLOADDATE DATE NULL,
    WAGECOUNT NUMBER(10,0) NULL
);

Insert into SAMPLE_DATA (YEAR,QUARTER,UPLOADDATE,WAGECOUNT) values ('2019','1',to_date('27-MAR-19','DD-MON-RR'),5);
Insert into SAMPLE_DATA (YEAR,QUARTER,UPLOADDATE,WAGECOUNT) values ('2019','1',to_date('28-MAR-19','DD-MON-RR'),8493);
Insert into SAMPLE_DATA (YEAR,QUARTER,UPLOADDATE,WAGECOUNT) values ('2019','1',to_date('29-MAR-19','DD-MON-RR'),15070);
Insert into SAMPLE_DATA (YEAR,QUARTER,UPLOADDATE,WAGECOUNT) values ('2019','1',to_date('30-MAR-19','DD-MON-RR'),1244);
Insert into SAMPLE_DATA (YEAR,QUARTER,UPLOADDATE,WAGECOUNT) values ('2020','1',to_date('03-JAN-20','DD-MON-RR'),0);
Insert into SAMPLE_DATA (YEAR,QUARTER,UPLOADDATE,WAGECOUNT) values ('2020','1',to_date('05-JAN-20','DD-MON-RR'),2);
Insert into SAMPLE_DATA (YEAR,QUARTER,UPLOADDATE,WAGECOUNT) values ('2020','1',to_date('06-JAN-20','DD-MON-RR'),3);
Insert into SAMPLE_DATA (YEAR,QUARTER,UPLOADDATE,WAGECOUNT) values ('2020','1',to_date('07-JAN-20','DD-MON-RR'),6);
Insert into SAMPLE_DATA (YEAR,QUARTER,UPLOADDATE,WAGECOUNT) values ('2021','2',to_date('21-APR-21','DD-MON-RR'),59);
Insert into SAMPLE_DATA (YEAR,QUARTER,UPLOADDATE,WAGECOUNT) values ('2021','2',to_date('22-APR-21','DD-MON-RR'),10);
Insert into SAMPLE_DATA (YEAR,QUARTER,UPLOADDATE,WAGECOUNT) values ('2021','2',to_date('23-APR-21','DD-MON-RR'),16);
Insert into SAMPLE_DATA (YEAR,QUARTER,UPLOADDATE,WAGECOUNT) values ('2021','2',to_date('24-APR-21','DD-MON-RR'),1);

Answer 1

你需要row_number解析函数：

select year, quarter, uploaddate, wagecount, 
       row_number()
         OVER (partition by year
               ORDER BY quarter, uploaddate) as SequentialNumbers 
from SAMPLE_DATA
order by year, quarter, uploaddate;

结果：

YEAR    QUARTER UPLOADDATE           WAGECOUNT SEQUENTIALNUMBERS
---- ---------- ------------------- ---------- -----------------
2019          1 2019-03-27 00:00:00          5                 1
2019          1 2019-03-28 00:00:00       8493                 2
2019          1 2019-03-29 00:00:00      15070                 3
2019          1 2019-03-30 00:00:00       1244                 4
2020          1 2020-01-03 00:00:00          0                 1
2020          1 2020-01-05 00:00:00          2                 2
2020          1 2020-01-06 00:00:00          3                 3
2020          1 2020-01-07 00:00:00          6                 4
2021          2 2021-04-21 00:00:00         59                 1
2021          2 2021-04-22 00:00:00         10                 2
2021          2 2021-04-23 00:00:00         16                 3
2021          2 2021-04-24 00:00:00          1                 4

在结果中添加一列，显示按年份分组的序号

Adding a column to the results that would show sequential numbers grouped based on year

oracle

group-by

sequential