如何在对 Promscale 的聚合查询中对标签进行分组
How to group on labels in aggregate query to Promscale
我正在创建 SQL 从 Grafana 到 Promscale 的查询。有指标和标签。我无法获得按某些标签分组的正确方法。我试过了:
SELECT time_bucket('$__interval', "time") AS "time",
AVG("value") AS "used"
FROM "disk_used_percent"
WHERE $__timeFilter("time") AND
"labels" ? ('host' == '$host_pg')
GROUP BY 1, "labels" --> 'path'
ORDER BY 1;
以及:
SELECT time_bucket('$__interval', "time") AS "time",
AVG("value") AS "used"
FROM "disk_used_percent"
WHERE $__timeFilter("time") AND
"labels" ? ('host' == '$host_pg')
GROUP BY 1, "path_id"
ORDER BY 1;
但分组似乎没有按预期工作。怎么了?相应的 PromQL 查询将是:
avg(disk_used_percent{host=~"$host_prom"}) by(path))
您可以使用VAL("<label>_id")
分组:
SELECT time_bucket('$__interval', "time") AS "time",
VAL("path_id") AS "path",
AVG("value") AS "used"
FROM "disk_used_percent"
WHERE $__timeFilter("time") AND
"labels" ? ('host' == '$host_pg')
GROUP BY 1, 2
ORDER BY 1;
旁注: 还要避免在 Grafana 中使用 $__timeFilter("time")
模板宏,因为它会生成以下谓词:
"time" BETWEEN 'time range begin' AND 'time range end'
这可能是
problematic在某些情况下。
我正在创建 SQL 从 Grafana 到 Promscale 的查询。有指标和标签。我无法获得按某些标签分组的正确方法。我试过了:
SELECT time_bucket('$__interval', "time") AS "time",
AVG("value") AS "used"
FROM "disk_used_percent"
WHERE $__timeFilter("time") AND
"labels" ? ('host' == '$host_pg')
GROUP BY 1, "labels" --> 'path'
ORDER BY 1;
以及:
SELECT time_bucket('$__interval', "time") AS "time",
AVG("value") AS "used"
FROM "disk_used_percent"
WHERE $__timeFilter("time") AND
"labels" ? ('host' == '$host_pg')
GROUP BY 1, "path_id"
ORDER BY 1;
但分组似乎没有按预期工作。怎么了?相应的 PromQL 查询将是:
avg(disk_used_percent{host=~"$host_prom"}) by(path))
您可以使用VAL("<label>_id")
分组:
SELECT time_bucket('$__interval', "time") AS "time",
VAL("path_id") AS "path",
AVG("value") AS "used"
FROM "disk_used_percent"
WHERE $__timeFilter("time") AND
"labels" ? ('host' == '$host_pg')
GROUP BY 1, 2
ORDER BY 1;
旁注: 还要避免在 Grafana 中使用 $__timeFilter("time")
模板宏,因为它会生成以下谓词:
"time" BETWEEN 'time range begin' AND 'time range end'
这可能是 problematic在某些情况下。