AttributeError: 'datetime.timedelta' object has no attribute 'split'

Question

我正在尝试通过以下代码获取与日期时间相差的小时数 '''

from datetime import datetime
from datetime import date 
from datetime import time
from datetime import timedelta
import sys
a = date.today()
b = datetime.now()
print("Today is :" +str(b))
q = int(input("enter your birth month :"))

w = int(input("enter your brth day :"))
my_bday = date(a.year,q,w)
#print(my_bday)
if my_bday < a :
     my_bday = my_bday.replace(year = a.year +1)

time_to_bday = abs (a -my_bday)
#print("The number of days remaining for your bday is :" +time_to_bday)
o = time_to_bday.split(' ')
z = o[0]
k = timedelta(days = z)
print("Time remaining for your bday is : " +str(b + k))

此处拆分不起作用并出现以下错误：

Traceback (most recent call last):
  File "f:/Ch2/practise.py", line 96, in <module>
    o = time_to_bday.split(' ')
AttributeError: 'datetime.timedelta' object has no attribute 'split'

我仔细检查了代码 o/p 直到 time_to_bday 如下：

PS F:\Ch2> & "C:/Users/sai kiran/AppData/Local/Programs/Python/Python36-32/python.exe" f:/Ch2/practise.py
Today is :2021-05-01 20:32:08.677781
enter your birth month :11
enter your brth day :17
200 days, 0:00:00

Answer 1

Timedelta 不是 str，所以没有 spilit()。 print() 将其转换为 str。例如，您需要调用 o=str(o)

Answer 2

你已经及时计算了delta，它不再是字符串了

time_to_bday是timedelta对象，可以直接获取days如下

time_to_bday.days

如果您想按小时打印，您可以使用 time_to_bday.days * 24

打印

From your code ::
enter your birth month :4
enter your brth day :17

    >> time_to_bday.days
    350

AttributeError: 'datetime.timedelta' object has no attribute 'split'

AttributeError: 'datetime.timedelta' object has no attribute 'split'

python

datetime

split

timedelta

python-3.x