C++ multi-threading Error: Single producer Multiple consumer

Question

我正在尝试实现单生产者多消费者，但是下面的代码无法编译。有人可以帮助解决这个错误吗？也可以从这个池中唤醒所有线程并且随机线程能够获取锁吗？

TIA

`
threadPool/main.cpp:4:
/Library/Developer/CommandLineTools/usr/bin/../include/c++/v1/thread:364:17:
error: no matching constructor for initialization of '_Gp' (aka 'tuple<unique_ptrstd::__1::__thread_struct, void (TestClass::*)(), TestClass>') new _Gp(std::move(__tsp), ^ ~~~~~~~~~~~~~~~~~
ls/usr/bin/../include/c++/v1/type_traits:2422:12: error: call to implicitly-deleted copy constructor of 'typename
decay::type' (aka 'TestClass') return _VSTD::forward<_Tp>(__t);
----------------------------------------------

#include <iostream>
#include <vector>
#include <queue>
#include <thread>
#include <condition_variable>

using namespace std;


class TestClass{

public:
    void producer(int i) {
        unique_lock<mutex> lockGuard(mtx);
        Q.push(i);
        lockGuard.unlock();
        cond.notify_all();
    }


    void consumer() {
        unique_lock<mutex> lockGuard(mtx);
        cond.wait(lockGuard, [this]() {
            return !Q.empty();
        });
        cout<<this_thread::get_id();
        cout<<Q.front()<<endl;
        Q.pop();
        lockGuard.unlock();
    };

private:
    mutex mtx;
    condition_variable cond;
    queue<int> Q;

};

int main() {
    std::cout << "Hello, World!" << std::endl;
    int MAX_THREADS = std::thread::hardware_concurrency()-1;
    vector<thread> ThreadVector;

    TestClass testObj;
    for(int i=0; i<MAX_THREADS; i++){
        ThreadVector.emplace_back(&TestClass::consumer, std::move(testObj));
        cout<<"Pool threadID:" <<ThreadVector[i].get_id()<<endl;
    }


    TestClass testObj2;
    for(int i=0; i<10; i++) {
        testObj.producer(i);
    }


    for(auto &&t : ThreadVector) {
        t.join();
    }

    return 0;
}


`

Another version to call threads
int main()
{
    std::vector<std::thread> vecOfThreads;
    std::function<void(TestClass&)> func = [&](TestClass &obj) {
        while(1) {
            obj.consumer();
        }
    };

    unsigned MAX_THREADS = std::thread::hardware_concurrency()-1;
    TestClass obj;
    for(int i=0; i<MAX_THREADS; i++) {
        std::thread th1(func, std::ref(obj));
        vecOfThreads.emplace_back(std::move(th1));
    }

   TestClass prod;
   for(int i=0; i<10; i++) {
       prod.producer(i);
   }
    for (std::thread & th : vecOfThreads)
    {
        if (th.joinable())
            th.join();
    }
    return 0;
}

Answer 1

std::move(testObj) 应该是 &testObj（指向调用 consumer 的对象的指针）- 或 std::ref(testobj)（变成 reference_wrapper（持有也是指向该对象的指针）。
您应该至少调用 produce 的次数与线程数一样多，否则程序将无法完成。
您不需要手动 unlock。守卫离开范围时会自动解锁。

示例：

class TestClass {
public:
    void producer(int i) {
        lock_guard<mutex> lockGuard(mtx); // here a lock_guard is enough
        Q.push(i);
        // no manual unlocking
        cond.notify_all(); 
    }

    void consumer() {
        unique_lock<mutex> lockGuard(mtx);
        cond.wait(lockGuard, [this] { return !Q.empty(); });
        cout << this_thread::get_id();
        cout << Q.front() << endl;
        Q.pop();
    };

private:
    mutex mtx;
    condition_variable cond;
    queue<int> Q;
};

int main() {
    std::cout << "Hello, World!" << std::endl;
    unsigned MAX_THREADS = std::thread::hardware_concurrency() - 1;
    vector<thread> ThreadVector;
    ThreadVector.reserve(MAX_THREADS); // since you know how many, reserve

    TestClass testObj;
    for(unsigned i = 0; i < MAX_THREADS; i++) {
        // here, &testobj
        ThreadVector.emplace_back(&TestClass::consumer, &testObj);

        cout << "Pool threadID:" << ThreadVector[i].get_id() << endl;
    }

    // produce MAX_THREADS of things to put in the queue:
    for(int i = 0; i < MAX_THREADS; i++) {
        testObj.producer(i);
    }

    for(auto&& t : ThreadVector) {
        t.join();
    }
}

关于您在评论部分的问题：如果您想保留 consumer 线程运行直到您告诉他们退出，您可以添加另一个变量（称为 run 这里）consumer 线程监控。

示例：

#include <condition_variable>
#include <iostream>
#include <queue>
#include <thread>
#include <vector>

using namespace std;

class TestClass {
public:
    void producer(int i) {
        lock_guard<mutex> lockGuard(mtx);
        Q.push(i);
        to_pool.notify_one();
    }

    void consumer() {
        while(true) {
            unique_lock<mutex> lockGuard(mtx);
            to_pool.wait(lockGuard, [this] { return !run || !Q.empty(); });

            if(!run) break; // time to quit

            cout << this_thread::get_id() << ' ' << Q.front() << endl;
            Q.pop();

            // Tell producer that we picked one from the queue.
            // if it's only interesting to notify when the queue is empty,
            // add: if(Q.empty())
            to_producer.notify_one();
        }
    };

    void stop() {
        lock_guard<mutex> lockGuard(mtx);
        run = false;            // tell all pool threads to quit
        to_pool.notify_all();
    }

    void wait_for_all_work_to_be_done() {
        std::unique_lock<mutex> lg(mtx);
        to_producer.wait(lg, [this] { return Q.empty(); });
    }

private:
    bool run = true;
    mutex mtx;
    condition_variable to_pool;
    condition_variable to_producer;
    queue<int> Q;
};

int main() {
    std::cout << "Hello, World!" << std::endl;
    unsigned MAX_THREADS = std::thread::hardware_concurrency() - 1;
    vector<thread> ThreadVector;
    ThreadVector.reserve(MAX_THREADS);

    TestClass testObj;
    for(unsigned i = 0; i < MAX_THREADS; i++) {
        ThreadVector.emplace_back(&TestClass::consumer, &testObj);

        cout << "Pool threadID:" << ThreadVector[i].get_id() << endl;
    }

    for(int i = 0; i < MAX_THREADS / 2; i++) {
        testObj.producer(i);
    }

    testObj.wait_for_all_work_to_be_done();

    // stop pool threads
    testObj.stop();

    for(auto&& t : ThreadVector) t.join();
}

C++ multi-threading Error: Single producer Multiple consumer

C++ multi-threading Error: Single producer Multiple consumer

c++

multithreading

producer-consumer

condition-variable