没有从字符串值反序列化的字符串参数 constructor/factory 方法 ('E1')

Question

无法将 xml 转换为 java pojo 对象。请查看以下详细信息：-

输入xml-

<?xml version='1.0' encoding='UTF-8'?>
<Company>
<Employee>
<Name>E1</Name>
<Id>123</Id>
</Employee>
<Employee>
<Name>E2</Name>
<Id>678</Id>
</Employee>
</Company>

pom.xml 有依赖关系：-

<dependency>
            <groupId>com.fasterxml.jackson.dataformat</groupId>
            <artifactId>jackson-dataformat-xml</artifactId>
            <version>2.9.6</version>
</dependency>

Company.Java

package com.test;
import java.util.List;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlProperty;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlRootElement;

@JacksonXmlRootElement
public class Company {
    
    @JacksonXmlProperty(localName = "Employee")
    private List<Employee> employee;
    
    public Company() {}

    public Company(List<Employee> employee) {
        super();
        this.employee = employee;
    }

    public List<Employee> getEmployee() {
        return employee;
    }

    public void setEmployee(List<Employee> employee) {
        this.employee = employee;
    }

    
}

Employee.java

package com.test;

import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlProperty;

public class Employee {
    
    @JacksonXmlProperty(localName = "Name")
    private String name;
    
    @JacksonXmlProperty(localName = "Id")
    private String id;
    
    public Employee() {}

    public Employee(String name, String id) {
        super();
        this.name = name;
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getId() {
        return id;
    }

    public void setId(String id) {
        this.id = id;
    }
    
    

}

将xml转换为java代码：-

JacksonXmlModule module = new JacksonXmlModule();
XmlMapper objectMapper = new XmlMapper(module);
module.setDefaultUseWrapper(false);
Company comapny = objectMapper.readValue(xml,Company.class);

将 xml 转换为 pojo

时出现以下错误

线程“主”中的异常com.fasterxml.jackson.databind.exc.MismatchedInputException：无法构造com.test.Employee的实例（尽管至少存在一个创建者）：没有字符串参数constructor/factory方法从字符串值反序列化('E1') 在 [来源：（StringReader）；行：4，列：7]（通过参考链：com.test.Employee[“公司”]->java.util.ArrayList[0]）

Answer 1

问题在于反序列化中全局 module.setDefaultUseWrapper(false) 的使用，而 DefaultUseWrapper 的使用应限于 [=15= 中的嵌套集合 List<Employee> employee ] class 与 @JacksonXmlElementWrapper(useWrapping = false) 如下所示：

@JacksonXmlRootElement
public class Company {
    
    @JacksonXmlProperty(localName = "Employee")
    @JacksonXmlElementWrapper(useWrapping = false)
    private List<Employee> employee;
    
    ...other fields, setters, getters and constructors from your code
}

您必须删除 module.setDefaultUseWrapper(false) 并重写您的主要 class，如下所示：

JacksonXmlModule module = new JacksonXmlModule();
XmlMapper objectMapper = new XmlMapper(module);
Company company = objectMapper.readValue(xml,Company.class);
System.out.println(objectMapper.writeValueAsString(company));

没有从字符串值反序列化的字符串参数 constructor/factory 方法 ('E1')

no String-argument constructor/factory method to deserialize from String value ('E1')

java

pojo

jackson

xml-parsing

jackson-dataformat-xml