将大纪元时间转换为本地时间

Question

log_input.log

1949,1603441909,984159,0.002608,19.8829994202,0.0,640.0
950,1603441910,  416274
21,160340, 24666082,0.002608,19.81913,0.0,638.0

检查列的一致性，列号不一致的忽略该行。读取第二列并将第二列转换为本地时间格式。

log_output.log

1949, 10-31-49,984159,0.002608,19.8829994202,0.0,640.0
21, 9-32-20, 24666082,0.002608,19.81913,0.0,638.0

代码：

with open('log_input.txt', 'r') as f:
    csv_data = csv.reader(f)
    csv_lines = list(csv_data)

for line in csv_lines:
  line[1] = convert(line[1].split(':')[1].strip())

Answer 1

您可以使用日期时间将纪元转换为日期：

time.strftime('%Y-%m-%d', time.localtime(<your epoch>))

如果不到一天，只要检查是否小于86400，如果是，就照原样写。

将大纪元时间转换为本地时间

Convert Epoch time to local time

python

datetime

epoch