如何显示一个由 pygame 中的点组成的圆圈?
How can a display a circle made of dots in pygame?
我有一个这样的像素对象:
class Pixel:
def __init__(self, screen, color, pos, size=8):
self.screen = screen
self.color = color
self.pos = pos
self.size = size
def update(self):
pygame.draw.circle(self.screen, self.color, self.pos, self.size)
我想创建一个输出,看起来像一个由这些 Pixel 对象组成的圆圈。到目前为止,我已经尝试过这样的程序:
# PyMate
import pygame
from pygame.colordict import THECOLORS
from drawing import Pixel, Frame
frame = Frame((800, 650))
frames = [frame]
pixels = []
x, y = 50, 50
li = []
for i in range(1000):
li.append(Pixel(frames[0], THECOLORS["orange"], (x, y)))
if i % 500 == 0:
x -= 0.002
y -= 0.006
else:
y += 0.006
x += 0.002
pixels.extend(li)
frames.append(frame)
running = True
while running:
frame = Frame((800, 650))
frames.append(frame)
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
for i in frames:
i.fill(THECOLORS["white"])
for i in pixels:
i.update()
del frame, frames[0]
pygame.display.update()
这种作品,但它画了一条直线(不是我想要的)。我真正关注的部分是:
for i in range(1000):
li.append(Pixel(frames[0], THECOLORS["orange"], (x, y)))
if i % 500 == 0:
x -= 0.002
y -= 0.006
else:
y += 0.006
x += 0.002
x和y的变化好像不对,模数好像也不对。它们可能是什么数字?
一种方法是用一个长度不变但角度变化的向量向前迈进:
x, y = 300, 200
step = 20
angle = 0
for i in range(36):
x -= math.sin(angle*math.pi/180) * step
y += math.cos(angle*math.pi/180) * step
angle += 10
pixels.append(Pixel(screen, "orange", (x, y)))
最小示例:
import pygame
import math
class Pixel:
def __init__(self, screen, color, pos, size=8):
self.screen = screen
self.color = color
self.pos = pos
self.size = size
def update(self):
pygame.draw.circle(self.screen, self.color, self.pos, self.size)
screen = pygame.display.set_mode((800, 650))
pixels = []
x, y = 300, 200
step = 20
angle = 0
for i in range(36):
x -= math.sin(angle*math.pi/180) * step
y += math.cos(angle*math.pi/180) * step
angle += 10
pixels.append(Pixel(screen, "orange", (x, y)))
running = True
while running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
screen.fill(0)
for p in pixels:
p.update()
pygame.display.update()
我有一个这样的像素对象:
class Pixel:
def __init__(self, screen, color, pos, size=8):
self.screen = screen
self.color = color
self.pos = pos
self.size = size
def update(self):
pygame.draw.circle(self.screen, self.color, self.pos, self.size)
我想创建一个输出,看起来像一个由这些 Pixel 对象组成的圆圈。到目前为止,我已经尝试过这样的程序:
# PyMate
import pygame
from pygame.colordict import THECOLORS
from drawing import Pixel, Frame
frame = Frame((800, 650))
frames = [frame]
pixels = []
x, y = 50, 50
li = []
for i in range(1000):
li.append(Pixel(frames[0], THECOLORS["orange"], (x, y)))
if i % 500 == 0:
x -= 0.002
y -= 0.006
else:
y += 0.006
x += 0.002
pixels.extend(li)
frames.append(frame)
running = True
while running:
frame = Frame((800, 650))
frames.append(frame)
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
for i in frames:
i.fill(THECOLORS["white"])
for i in pixels:
i.update()
del frame, frames[0]
pygame.display.update()
这种作品,但它画了一条直线(不是我想要的)。我真正关注的部分是:
for i in range(1000):
li.append(Pixel(frames[0], THECOLORS["orange"], (x, y)))
if i % 500 == 0:
x -= 0.002
y -= 0.006
else:
y += 0.006
x += 0.002
x和y的变化好像不对,模数好像也不对。它们可能是什么数字?
一种方法是用一个长度不变但角度变化的向量向前迈进:
x, y = 300, 200
step = 20
angle = 0
for i in range(36):
x -= math.sin(angle*math.pi/180) * step
y += math.cos(angle*math.pi/180) * step
angle += 10
pixels.append(Pixel(screen, "orange", (x, y)))
最小示例:
import pygame
import math
class Pixel:
def __init__(self, screen, color, pos, size=8):
self.screen = screen
self.color = color
self.pos = pos
self.size = size
def update(self):
pygame.draw.circle(self.screen, self.color, self.pos, self.size)
screen = pygame.display.set_mode((800, 650))
pixels = []
x, y = 300, 200
step = 20
angle = 0
for i in range(36):
x -= math.sin(angle*math.pi/180) * step
y += math.cos(angle*math.pi/180) * step
angle += 10
pixels.append(Pixel(screen, "orange", (x, y)))
running = True
while running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
screen.fill(0)
for p in pixels:
p.update()
pygame.display.update()