python 中带有打印函数的 eval() 函数出错
Error with eval() function with print function in python
我正尝试 运行 在 Python 空闲中执行此操作:
>>> eval(print("123*13"))
我得到了正确的输出,但它带有 TypeError
:
123*13
Traceback (most recent call last):
File "<pyshell#4>", line 1, in <module>
eval(print("123*13"))
TypeError: eval() arg 1 must be a string, bytes or code object
注意:
我不想 print(eval("123*13"))
。
我想在 eval()
函数中使用 print()
。
这不是针对实际实现的,但是我在使用 eval()
函数时遇到了这个错误。我不是要求任何实际实施,而是出于好奇。
使用它:
eval('print("123*13")')
在 eval() 源代码中:
evel (__source: str | bytes | CodeType, __globals: Dict[str, Any] | None = ..., __locals: Mapping[str, Any] | None = ...) -> Any
'''Evaluate the given source in the context of globals and locals.
The source may be a string representing a Python expression
or a code object as returned by compile().
The globals must be a dictionary and locals can be any mapping,
defaulting to the current globals and locals.
If only globals is given, locals defaults to it.'''
...
评估帮助():
eval(source, globals=None, locals=None, /)
Evaluate the given source in the context of globals and locals.
The source may be a string representing a Python expression
or a code object as returned by compile().
The globals must be a dictionary and locals can be any mapping,
defaulting to the current globals and locals.
If only globals is given, locals defaults to it.
您可以在 Python.org 中查看更多内容。
我正尝试 运行 在 Python 空闲中执行此操作:
>>> eval(print("123*13"))
我得到了正确的输出,但它带有 TypeError
:
123*13
Traceback (most recent call last):
File "<pyshell#4>", line 1, in <module>
eval(print("123*13"))
TypeError: eval() arg 1 must be a string, bytes or code object
注意:
我不想 print(eval("123*13"))
。
我想在 eval()
函数中使用 print()
。
这不是针对实际实现的,但是我在使用 eval()
函数时遇到了这个错误。我不是要求任何实际实施,而是出于好奇。
使用它:
eval('print("123*13")')
在 eval() 源代码中:
evel (__source: str | bytes | CodeType, __globals: Dict[str, Any] | None = ..., __locals: Mapping[str, Any] | None = ...) -> Any
'''Evaluate the given source in the context of globals and locals.
The source may be a string representing a Python expression
or a code object as returned by compile().
The globals must be a dictionary and locals can be any mapping,
defaulting to the current globals and locals.
If only globals is given, locals defaults to it.'''
...
评估帮助():
eval(source, globals=None, locals=None, /)
Evaluate the given source in the context of globals and locals.
The source may be a string representing a Python expression
or a code object as returned by compile().
The globals must be a dictionary and locals can be any mapping,
defaulting to the current globals and locals.
If only globals is given, locals defaults to it.
您可以在 Python.org 中查看更多内容。