Django 问题 'ModelChoiceField' 对象没有属性 'use_required_attribute'

Django Question 'ModelChoiceField' object has no attribute 'use_required_attribute'

亲爱的, 我在 Django 中遇到了一个问题。 关于'ModelChoiceField' object has no attribute 'use_required_attribute' 的错误,我不知道我在哪里弄错了。

我的目标是使我的提交自定义表单,但我不明白 Django 中的 CBV 是如何实现这个目标的,所以我回去使用 Django 中的 forms.py 和 FBV。但是我在表单模型中的字段有外键来引用其他模型。 我使用 forms.ModelChoiceField 并希望解决外键问题,但它不起作用并显示此错误。

感谢您的阅读,希望有人能帮我解决。

这是我的代码:

forms.py

    from django import forms
    from .models import Case
    from school_app.models import School
    from student_app.models import Student
    class CaseModelForm(forms.ModelForm):
    
        class Meta:
            model = Case
            fields='__all__'
            widgets = {
                'name' : forms.ModelChoiceField(queryset=Student.objects.all()),
                'phone' : forms.TextInput(),
                'school' :forms.ModelChoiceField(queryset=School.objects.all())
}

models.py

    from django.db import models
    from django.urls import reverse
    import datetime,time
    from school_app.models import School
    from student_app.models import Student
    # Create your models here.
    class Case(models.Model):
        name=models.ForeignKey(Student,related_name='case_student_name',on_delete=models.CASCADE,verbose_name="姓名")
        phone=models.CharField(verbose_name="電話",blank=False,max_length=256)
        school=school=models.ForeignKey(School,related_name='case_school',on_delete=models.CASCADE,verbose_name="學校")

views.py

def CaseFormView(request):
    print("CaseForm")
    form_cus = CaseModelForm()
    if request.method == "POST":
        form = CaseModelForm(request.POST)
        if form.is_valid():
            form.save()
        return redirect("/")

    context={
        'form_cus': form_cus
    }
    return render(request, 'case_app/case_form.html',context)

urls.py

from student_app import views
from django.urls import path
app_name = 'student_app'

urlpatterns=[
    path('', views.StudentListView.as_view(),name='list'),
    path('<int:pk>/', views.StudentDetailView.as_view(), name='detail'),
    path('create/',views.StudentCreateView.as_view(), name='create')]

case_form.html

<form method="post">
    {% csrf_token %}
    
    <div class="form-group">
        <div class="form-group col-md-6">
            <label>{{form_cus.name.label}}</label>

            {{form_cus.name}}
        </div>
        <div class="form-group col-md-6">
            <label>{{form_cus.school.label}}</label>

            {{form_cus.school}}
        </div>
        {{form_cus}}
    <input type="submit" class="btn btn-primary" value="提交"> 
       
    </div>
    {% if not form.instance.pk %}
    <a class='btn btn-secondary' href="{% url 'case_app:list' %}">取消</a>
    {% else %}
    <a class='btn btn-secondary' href="{% url 'case_app:detail' pk=form.instance.pk %}">取消</a>
    {% endif %}
</form>

谢谢!

A ModelChoiceField 不是 小部件,它是一个 表单字段 ,因此您可以将其实现为:

from django import forms
from .models import Case
from school_app.models import School
from student_app.models import Student

class CaseModelForm(forms.ModelForm):
    <b>school =</b> forms.ModelChoiceField(queryset=School.objects.all())
    <b>name =</b> forms.ModelChoiceField(queryset=Student.objects.all())

    class Meta:
        model = Case
        fields='__all__'
        widgets = {
            'phone' : forms.TextInput(),    
        }

由于 schoolname 在您的 Case 模型中是 ForeignKey,您不需要指定这些:我们可以实现 CaseModelForm 与:

from django import forms
from .models import Case
from school_app.models import School
from student_app.models import Student

class CaseModelForm(forms.ModelForm):
    # no school/name field
    class Meta:
        model = Case
        fields='__all__'
        widgets = {
            'phone' : forms.TextInput(),    
        }