Laravel 存储库和控制器

Question

这是我的存储库

public function showInterface(int $id)
    {
        $role = $this->model->find($id);

        $rolePermissions = Permission::join("role_has_permissions","role_has_permissions.permission_id","=","permissions.id")
            ->where("role_has_permissions.role_id",$id)
            ->get();


        return $role && $rolePermissions;
    }

这是我的控制器

 public function show($id)
    {
        $role=$this->repository->showInterface($id);

        return view('roles.show',compact('role'));
    }

问题是我应该在 Controller 中压缩 $role 和 $rolePermissions，我应该怎么做？

Answer 1

我认为你应该将其更改为：


public function showInterface(int $id)
    {
        $role = $this->model->find($id);

        $rolePermissions = Permission::join("role_has_permissions","role_has_permissions.permission_id","=","permissions.id")
            ->where("role_has_permissions.role_id",$id)
            ->get();


        return [$role, $rolePermissions];
    }

和

public function show($id)
    {
        [$role, $rolePermissions] = $this->repository->showInterface($id);

        return view('roles.show',compact('role', 'rolePermissions'));
    }

Laravel 存储库和控制器

Laravel repository and controller

php

repository

laravel