如何在列表中找到列表中的最大数量？

Question

我有列表中的概率再次出现在列表中，我如何从中获得最大数量，在这种情况下它应该 return 0.20 数字。

     [[0.     0.     0.     0.     0.     0.     0.     0.     0.     0.13
      0.     0.     0.     0.1465 0.01   0.     0.     0.     0.     0.
      0.     0.01   0.     0.     0.     0.     0.     0.     0.     0.
      0.02   0.     0.     0.     0.     0.     0.     0.     0.     0.
      0.     0.     0.     0.     0.     0.     0.03   0.     0.01   0.
      0.     0.01   0.     0.01   0.     0.     0.     0.     0.     0.
      0.     0.     0.     0.     0.     0.     0.     0.     0.     0.
      0.     0.     0.     0.     0.     0.     0.     0.     0.     0.
      0.     0.05   0.     0.     0.     0.     0.     0.     0.     0.
      0.     0.     0.     0.     0.     0.     0.     0.     0.     0.
      0.     0.01   0.     0.     0.     0.     0.07   0.     0.     0.
      0.     0.     0.     0.     0.     0.     0.04   0.     0.     0.
      0.     0.     0.     0.     0.     0.     0.     0.01   0.     0.
      0.     0.     0.     0.     0.     0.16   0.     0.     0.     0.
      0.     0.     0.     0.     0.     0.     0.     0.     0.     0.03
      0.     0.     0.     0.     0.2035 0.     0.     0.05   0.    ]]

Answer 1

max(max(x) for x in my_list)

或

max(sum(my_list, []))

或

import numpy as np
np.max(my_list)

Answer 2

试试这个 pythonic 解决方案：

max_ = max(max(list_))
print(max_)

它应该给出所需的输出。