将外发邮件移至回收站

Question

我有一个脚本可以接收来自特定发件人的邮件并将它们发送到另一封电子邮件代码是：

function send() {
  let addressForSearch = 'aaaaaa@mail.com' // the senders email
  let emailForTransfer = 'bbbbbb@mail.com' // the final recipients email
  let messages = GmailApp.search(`from:${addressForSearch}`)
  if (messages.length > 0) {
    messages.forEach(function (m) {
      let message = m.getMessages()[0]
      let subject = message.getSubject()
      let body = message.getBody()
      let attachments = message.getAttachments()
      MailApp.sendEmail(emailForTransfer, subject, '', {
        htmlBody: body,
        attachments: attachments
      })
    })
  }
}

问题是，我如何删除（移至垃圾箱）我通过脚本发送并现在位于 'is sent' 中的邮件？

Answer 1

发送电子邮件后，您可以为发送给最终收件人的电子邮件创建另一个搜索并使用 GmailApp:moveThreadsToTrash(threads)。

将此添加到您的代码中：

 let threads = GmailApp.search(`to:${emailForTransfer}`)
  if (thread.length > 0) {
    GmailApp.moveThreadsToTrash(threads);
  }

此外，请注意 MailApp 的功能有限（仅限 getRemainingDailyQuota() 和 sendEmail()）。参见 documentation

Answer 2

好的，我所做的是，我在邮件中插入了一个隐藏的 Uuid，这样我就有了一种搜索特定电子邮件的方法。这是代码

function redirect() {
  let emailForTransfer = '****123@gmail.com' // the final recipients email
  let addressForSearch = GmailApp.search(`from:***123@gmail.com is:unread`) //the senders email
  if (addressForSearch.length > 0) {
    for (let formessage of addressForSearch) {
      let message = formessage.getMessages()[0]
      let subject = message.getSubject()
      let body = message.getBody()
      let attachments = message.getAttachments()
      var searchTerm = Utilities.getUuid();
      var uidText = '<span style="color:transparent; display:none !important; height:0; opacity:0; visibility:hidden; width:0">' + searchTerm +  '</span>';
      GmailApp.sendEmail (emailForTransfer, subject, '', {
        htmlBody: body + uidText,
        attachments: attachments
        });
        Utilities.sleep(2000);
        GmailApp.search(searchTerm)[0].moveToTrash()
    }
  }
}

将外发邮件移至回收站

Moving an outgoing message to trash

gmail

google-apps-script