Bash 用于快速查看 VM 管理程序 (KVM) 的脚本

Question

我正在寻找一种在寻找来宾虚拟机 (运行 KVM) 时快速查看管理程序的方法。

我有一个脚本将我所有的虚拟机管理程序（带有来宾虚拟机）收集到一个由换行符分隔的文本文件中（参见下面的示例）：

Hypervisor: hypervisor1
 ID    Name                           State
----------------------------------------------------
 1     vm1                            running
 2     vm2                            running
 3     vm3                            running
 4     vm4                            running

Hypervisor: hypervisor2
 ID    Name                           State
----------------------------------------------------
 1     vm1                            running
 2     vm2                            running
 3     vm3                            running
 4     vm4                            running
 5     vm5                            running
 6     vm6                            running

ETC....

我试过：

grep -v -E "(-|Name)" file.txt |
awk -F ' ' '{print }' |
tr "\n" " " |
sed "s/ * / -> /"

但我明白了：

hypervisor1 -> vm1 vm2 vm3 vm4  hypervisor2 vm1 vm2 vm3 vm4 vm5 vm6

我的问题是：如何显示它？

hypervisor1 -> vm1 vm2 vm3 vm4
hypervisor2 -> vm1 vm2 vm3 vm4 vm5 vm6
etc.. etc...

Answer 1

根据您展示的示例，请您尝试以下操作。

awk '
/Hypervisor:/{
  if(value1){
    print value,value1
  }
  found=value1=""
  value=$NF
  next
}
/ID/{
  found=1
  next
}
found && match([=10=],/vm[0-9]+/){
  value1=(value1?value1 OFS:"")substr([=10=],RSTART,RLENGTH)
}
END{
  if(value1){
    print value,value1
  }
}
'  Input_file

说明： 为以上添加详细说明。

awk '                             ##Starting awk program from here.
/Hypervisor:/{                    ##Checking condition if line contains Hypervisor: then do following.
  if(value1){                     ##Checking if value1 is NOT NULL.
    print value,value1            ##Printing value and value1 here.
  }
  found=value1=""                 ##Nullify found and value1 here.
  value=$NF                       ##Setting value as last field here.
  next                            ##next will skip all further statements from here.
}
/ID/{                             ##Checking condition if ID is found in current line then do following.
  found=1                         ##Setting found to 1 here.
  next                            ##next will skip all further statements from here.
}
found && match([=11=],/vm[0-9]+/){    ##Checking if found is SET and match function to match vm values.
  value1=(value1?value1 OFS:"")substr([=11=],RSTART,RLENGTH)
                                  ##Creating value1 which has matched sub string and keep adding its values to it.
}
END{                              ##Starting END block of this program from here.
  if(value1){                     ##Checking condition if value1 is set then do following.
    print value,value1            ##Printing value and value1 here.
  }
}
'  Input_file                     ##Mentioning Input_file name here.

Answer 2

使用 awk:

awk '/Hypervisor:/ {printf "%s ->", } # row contains Hypervisor:
     [=10=]==""        {print ""}           # row is empty
     ~/[0-9]/    {printf " %s", }   # first column contains digit
     END           {print ""}' file     # add a trailing newline

输出：

hypervisor1 -> vm1 vm2 vm3 vm4
hypervisor2 -> vm1 vm2 vm3 vm4 vm5 vm6

Answer 3

这可能对你有用 (GNU sed)：

sed -E '/Hypervisor:/{s/.*: //;:a;x;/./{s/\n/ -> /;s// /g;p};x;h;d}
        /^\s*[0-9]+\s*(\S+).*/{s///;H};$!d;ba' file

将相关详细信息存储在 hold space 中，并在管理程序或文件末尾发生更改时，将存储的值处理为所需格式。

Bash 用于快速查看 VM 管理程序 (KVM) 的脚本

Bash script for viewing VM quickly the hypervisor (KVM)

awk

sed

kvm

hypervisor