Python 字典键和值问题

Question

我有一个元组列表，我希望将其用作新的值词典.
我有一个字符串列表，我希望将其用作键我的新词典。
不过我想用首都作为键对于嵌套字典。

    users = [
        (0, "Bob", "Paris", "password"),
        (1, "Jack", "Berlin", "python"),
        (2, "Jenna", "London" ,"overflow"),
        (3, "Eva", "Stockholm" ,"1234")
    ]
    
    
    office_employees = ["id","Name","key"]

我期望的输出如下：

    {'Paris':{"id":0,"Name":"Bob",key:"password"},'Berlin':{"id":1,"Name":"Jack",key:"python"},"London":{"id":2,"Name":"Jenna",key:"overflow"},"Stockholm":{"id":3,"Name":"Eva",key:"1234"}}

所以我用了字典理解。我尝试了各种过滤选项，但似乎没有任何效果。

    {item[2]: dict(zip(office_employees, item)) for index, item in enumerate(users)}

我收到的输出：

    {'Berlin': {'Name': 'Jack', 'id': 1, 'key': 'Berlin'},
     'London': {'Name': 'Jenna', 'id': 2, 'key': 'London'},
     'Paris': {'Name': 'Bob', 'id': 0, 'key': 'Paris'},
     'Stockholm': {'Name': 'Eva', 'id': 3, 'key': 'Stockholm'}}

Answer 1

这是你想要的吗？只需要使用索引：

users = [
        (0, "Bob", "Paris", "password"),
        (1, "Jack", "Berlin", "python"),
        (2, "Jenna", "London" ,"overflow"),
        (3, "Eva", "Stockholm" ,"1234")
    ]


office_employees = ["id","Name","key"]

d = {item[2]: dict(zip(office_employees, (item[0], item[1], item[3]))) for item in users}
print(d)

所以基本上是为了压缩你可以使用：

dict(zip(office_employees, (item[0], item[1], item[3])))

Answer 2

这里有一个有点丑陋的方法来实现你想要的。

代码：

users = [
        (0, "Bob", "Paris", "password"),
        (1, "Jack", "Berlin", "python"),
        (2, "Jenna", "London" ,"overflow"),
        (3, "Eva", "Stockholm" ,"1234")
    ]
office_employees = ["id","Name","key"]
ans = {}
for user in users:
    ans[user[2]]={office_employees[0]:user[0],office_employees[1]:user[1],office_employees[2]:user[3]}
print(ans)

结果：

{'Paris': {'id': 0, 'Name': 'Bob', 'key': 'password'}, 'Berlin': {'id': 1, 'Name': 'Jack', 'key': 'python'}, 'London': {'id': 2, 'Name': 'Jenna', 'key': 'overflow'}, 'Stockholm': {'id': 3, 'Name': 'Eva', 'key': '1234'}}

Answer 3

Therefore I used dictionary comprehension.

如果不方便，请不要使用字典理解。

d = {}
for u in users:
    id_, name, capital, key = u
    d[capital] = {
        'id': id_,
        'Name': name,
        'key': key
    }

这样就简单多了

Answer 4

我认为在创建嵌套字典之前，您需要将首都放入另一个数组中。

cap_cities = [用户中用户的用户[2]]

Python 字典键和值问题

Python Dictionary Key and Values Question

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