Python 函数 returns x 个月前的第一天和最后一天

Question

以下 python 代码 return 是上个月的 first/last 天，但我希望能够 return 3 个月前的第一天 [= =14=]

from datetime import date, timedelta

last_day_of_prev_month = date.today().replace(day=1) - timedelta(days=1)
start_day_of_prev_month = date.today().replace(day=1) - timedelta(days=last_day_of_prev_month.day)
print("First day of prev month:", start_day_of_prev_month)
print("Last day of prev month:", last_day_of_prev_month)

当前输出

#First day of prev month: 2021-04-01
#Last day of prev month: 2021-04-30

Answer 1

您可以将月数转换为周数：

from datetime import date, timedelta


def get_date_range(month_ago):
    weeks = month_ago * 4
    today = date.today()
    last_day_of_prev_month = today.replace(day=1) - timedelta(days=1)
    past_day = last_day_of_prev_month.replace(day=1) - timedelta(weeks=weeks)
    print("First day of prev month:", last_day_of_prev_month)
    print("Last day of prev month:", past_day.replace(day=1))


get_date_range(3)
get_date_range(6)

输出：

First day of prev month: 2021-04-30
Last day of prev month: 2021-01-01

First day of prev month: 2021-04-30
Last day of prev month: 2020-10-01

Python 函数 returns x 个月前的第一天和最后一天

Python function that returns first day and last day from x months ago

python

datetime

timedelta

maxdate

mindate