打字稿以简单的方式找到两个对象数组之间的区别

Question

我有一个如下所示的数组对象

allRoles = 
[
    { id: "0", name: "Tester", description: "Role is testing" },
    { id: "1", name: "Developer", description: "Role is Developer" },
    { id: "2", name: "Admin", description: "Role is Admin" },
    { id: "3", name: "Manager", description: "Role is Manager" },
    { id: "4", name: "Reviewer", description: "Role is Reviewer" }
]

assignedRoles = 
[
    { id: "0", name: "Tester", description: "Role is testing" },
    { id: "4", name: "Reviewer", description: "Role is Reviewer" }
]

将 id 视为每个对象的唯一我需要输出为

allowedRoles = 
[
    { id: "1", name: "Developer", description: "Role is Developer" },
    { id: "2", name: "Admin", description: "Role is Admin" },
    { id: "3", name: "Manager", description: "Role is Manager" }
]

有很多答案都在使用 for 循环或比较器。我想找出的是非常简单的解决方案，而不是编写复杂的代码。

Answer 1

幸运的是我能够弄清楚并找到非常简单的答案。就一个班轮!!!

this.allowedRoles=this.allRoles.filter(role=> !this.assignedRoles.some(present=> present.id==role.id));

打字稿以简单的方式找到两个对象数组之间的区别

Typescript find difference between two array of objects in simple way

javascript

ecmascript-5

typescript

angular

angular9