Django 中有序、过滤的查询集中的下一个或上一个项目

Question

如何从 post_details(DetailView) 过渡到下一篇文章，以便下一篇和上一篇文章都可用？

vievs.py

class HomeView(ListView):
    model = Post
    #queryset = Post.objects.filter(status=1)
    cats = Category.objects.all()
    template_name = 'home.html'
    #ordering = ['-post_date']
    paginate_by = 6

    def get_context_data(self, *args, **kwargs):
        cat_menu = Category.objects.all()
        context = super(HomeView, self).get_context_data(*args, **kwargs)
        context["cat_menu"] = cat_menu
        return context


class ArticleDetailView(HitCountDetailView):
    model = Post
    template_name = 'post_detail.html'
    count_hit = True


    def get_context_data(self, *args, **kwargs):
        cat_menu = Category.objects.all()
        context = super(ArticleDetailView, self).get_context_data(*args, **kwargs)
        
        stuff = get_object_or_404(Post, id=self.kwargs['pk'])
        total_likes = stuff.total_likes()

        context["cat_menu"] = cat_menu
        context["total_likes"] = total_likes

        return context

按日期和 ID 排序

Answer 1

如果您想要基于 DateTimeField 的上一个或下一个项目，您可以使用 .get_previous_by_<i>fieldname</i>(…) [Django-doc] or .get_next_by_<i>fieldname</i>(…) [Django-doc]。因此，您可以获得 stuff 的 previous/next 项目：

try:
    prev_stuff = stuff<b>.get_previous_by_post_date()</b>
except Stuff.DoesNotExist:
    prev_stuff = None

try:
    next_stuff = stuff<b>.get_next_by_post_date()</b>
except Stuff.DoesNotExist:
    next_stuff = None

Django 中有序、过滤的查询集中的下一个或上一个项目

next or previous item within an ordered, filtered queryset in Django

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